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yuyundonghui
参加运动会的 个学校编号为 。比赛分成 个男子项目和 个女子项目，项目编号分别为 和 。由于各项目参加人数差别较大，有些项目取前五名，得分顺序为7，5，3，2，1；还有些项目只取前三名，得分顺序为5，3，2。写一个统计程序产生各种成绩单和得分报表。
2、要求产生各学校的成绩单，内容包括各校所取得的每项成绩的项目号、名次（成绩）、姓名和得分；产生团体总分报表，内容包括校号、男子团体总分、女子团体总分和团体总分。
3、测试数据：对于 ， ， ，编号为奇数的项目取前五名，编号为偶数的项目取前三名，设计一组实例数据。
(The school serial number participating in Games is. Competition divides into men s event and women s event , the project serial number parts for the sum. The difference is bigger since every project participates in a number , some projects choose the first five , score order is 7 , 5 , 3 , 2 , 1 Still have some of projects taking the first three places , score only being 5 , 3 , 2 in proper order. Write a form for report counting procedure producing the various school report card and score. 2, demands the school report card producing every school , content includes every achievement project number , position in a name list (achievement) , full name and score per got by school Produce the group total points form for report , content including the school number , male person group total points , woman group total points and group total points. 3, testing data: Be that the odd number project chooses the first five to the serial number, the serial number is that the even number project c)
- 2009-04-07 22:40:37下载
- 积分：1
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PRIM
PRIM算法 对任意给定的网和起点，用PRIM算法的基本思想求解出所有的最小生成树。(PRIM algorithm for any given network and the starting point, PRIM algorithm used to solve the basic idea of all the minimum spanning tree.)
- 2009-01-11 19:05:21下载
- 积分：1
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MyGPS
1>实现可以随意浏览任一景点的介绍。（功能一）
2>可以给出任意两个景点的最短距离及其路线。（功能二）
3>可以查看任一景点热度，并可以对对所有景点热度（访问次数）进行排序。（功能三）
4>每个景点相关内容从文件读取，实现对文件操作的练习。
(1> implementations can feel free to browse introduce 任一景 points. (Function a)
2> You can give the shortest distance and route between any two attractions. (Function b)
3> You can view Renyi Jing point heat, and heat can all attractions (visits) to be sorted. (Function c)
4> each spot related content file reading, to achieve the file operations exercises.)
- 2015-11-12 22:16:01下载
- 积分：1
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d
说明： 有助于c++的初学者在平日的学习中更好的学习(Contribute to better learning c++ beginners learning on weekdays)
- 2013-11-29 14:32:18下载
- 积分：1
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bahuanghouwenti
八皇后问题，用vc编写了一个可以解决八皇后问题的程序，实现了递归调用。(The eight queens problem, using vc write a means of solving the eight queens problem program to achieve the recursive calls.)
- 2009-09-10 17:59:25下载
- 积分：1
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the-dynamic-planning
本文讨论了动态规划这一思想的核心内容和其基本特点，探讨了动态规划思想的适用范围，动态规划子问题空间和递推关系式确立的一般思路。(This paper discusses the dynamic planning this thought core content and its basic characteristics, this paper discusses the dynamic planning idea, the applicable scope of the dynamic programming problem space and son recursive formula of the establishment of general thoughts.
)
- 2011-12-15 16:49:05下载
- 积分：1
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DouglasPeucker
道格拉斯—普克法(Douglas—Peucker)的C++程序(Douglas- Puck method (Douglas-Peucker) of the C++ program)
- 2011-08-28 19:04:29下载
- 积分：1
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dxsjjc
多项式加减乘 用数据节够得算法实现多项式的加减乘 原理简单易懂(suoxiangshi jiajiancheng)
- 2009-12-29 11:13:13下载
- 积分：1
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Huffman-Tree
使用三叉链表实现的哈夫曼树,统计inputfile1.txt中各字符的出现频率，并据此构造Huffman树，编制Huffman 码；根据已经得到的编码，对01形式的编码段进行译码。
具体的要求：
1．将给定字符文件编码，生成编码，输出每个字符出现的次数和编码；
2．将给定编码文件译码，生成字符，输出编码及其对应字符。
(Emergence of the frequency of each character in the trigeminal lists using the Huffman tree, statistics inputfile1.txt, and accordingly the Huffman tree structure, preparation of Huffman code according to the coding has been. 01 to form the code segment for decoding.
Specific requirements:
1 coding the given character file, generating the encoding, and outputting the number and encoding of each character
2 will be given the encoding file decoding, generating the character, the output code and its corresponding character.)
- 2015-05-22 15:37:03下载
- 积分：1
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process_schedule
演示进程调度算法 使用的链表 包涵7个功能 4个算法(Process Scheduling Algorithm Demo
)
- 2011-12-24 10:52:17下载
- 积分：1
