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yinhangmoni
这是一个简单的银行模拟系统
1、 客户的到达时间随机
2、 客户需要处理的业务随机（不同业务处理的平均长度不同，例如：取款时间较短，开户和销户时间较长）
3、 处理客户业务所需时间随机（在一定范围内）
4、 使用文本文件记录每个客户到达时间、业务处理时间、业务结束时间
5、 动态显示（刷新时间可调）目前每个窗口累计处理客户数量、等待人数，每个窗口的平均业务处理时间，不同业务类型业务的累计办理量。
(This is a simple bank simulation system
1 customer arrival time random
2, customers need to deal with the business of random (the average length of the different business processes, such as: the withdrawal shorter, longer to open an account and cancel the account)
3, the time required to deal with customer service random (within certain limits)
4, using a text file to record each customer arrival time, business processing time, the business end of time
5 dynamically display (refresh time is adjustable) each window is accumulated to handle the number of customers waiting for the number the average business processing time of each window, different type of business operations total for the amount.)
- 2012-11-22 00:08:18下载
- 积分：1
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optional-project-blackjact
经典数据结构作业，黑杰克游戏。要求程序可以连续打10次，每场比赛的赢家，赢得一个点（两点一倍）。在结束的10场比赛为你和电脑打印出的总奖金。(Write a program that simulates a simplified version of the game "BlackJack". A deck of cards numbered 2 to 10, jacks, queens, kings, and aces is used, where jacks, queens and kings are counted as 10s, and aces are either 1 or 11 at your choice. )
- 2012-12-08 11:46:33下载
- 积分：1
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EightQueen
经典的 数据结构问题 八皇后问题。问题是在8*8的棋盘上放置棋子，要求每条直线上不能出现两个或以上的棋子。(The classical data structure problem Eight queens problem.Question is placed on the 8* 8 board piece, requirements on each line cannot appear two or more pieces.)
- 2016-11-23 10:30:11下载
- 积分：1
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a
说明： 进程死锁.资源分配图的绘制 建立所需数据结构；
使用题目21存成的资源分配图的文件作为输入；
编写资源分配图化简算法；
每化简一步，在屏幕上显示化简的当前结果；
最后给出结论，是否死锁，如思索给出死锁的进程及资源；
(Process deadlock. Resource allocation mapping establish the required data structures Use title 21 deposit into resource allocation graph file as input writing resource allocation map simplification algorithm Each simplification step, on-screen display simplification of the current result Finally, the conclusion of a deadlock, deadlock is given as thinking processes and resources )
- 2013-07-04 19:50:58下载
- 积分：1
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FindMax
求矩阵的最大值
有一个整型二维数组，大小为m行n列，要求分别找出其中最大值所在的行和列，以及该矩阵中的最大值。
要求：
1.编写自定义函数MaxVal
函数的原型为：int MaxVal(int arr[][N], int *m, int *n)
功能：
数组中最大元素的值通过MaxVal函数的返回值传递给主函数，最大元素的行值和列值分别通过m和n传递给主程序相应的变量。
2.main主函数的功能
（1）变量定义
（2）输入数组各元素的值
（3）以二维矩阵形式输出数组中各元素的值
（4）调用MaxVal函数，或者insert函数
（5）输出数组中最大元素的值和该数组元素的行值和列值。
3.所有关于数组的操作尽量使用指针
(FindMax)
- 2010-10-12 23:15:24下载
- 积分：1
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tanxinfangfa
说明： 贪心方法是一种改进了的分级处理方法。它首先根据题意，选取一种量度标准。然后按这种量度标准对这n个输入排序，并按排序一次输入一个量。如果这个输入和当前已构成在这种量度意义下的部分最优解加在一起不能产生一个可行解，则不把此解输入加到这部分解中。这种能够得到某种度量意义下的最优解的分级处理方法称为贪心方法。(greedy method is an improvement of the classification methods. According to its first title Italy, and a selection of standards of measurement. Then, under such a standard measure of this sort n input, with an input an order volume. If the input current and constitutes a measure of significance in this part of the optimal solution together not produce a feasible solution. this solution will not put this added to the importation of decomposition. This can be a meaningful measure of the optimal solution hierarchical method, known as greedy method.)
- 2006-05-15 21:50:01下载
- 积分：1
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maze
通过学习奥赛培训课程，利用回溯加递归的编程技巧完成的迷宫问题(Training courses through learning Orsay, plus use of recursive programming skills back to complete the maze problem)
- 2010-09-02 21:43:32下载
- 积分：1
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yuesehuhuan
就是一个简单的约瑟夫环实现程序。主要就是在痛过程序实现栈的实现。(Joseph is a simple procedure to achieve ring. The main program is in pain over the realization of the realization of the stack.)
- 2007-11-22 11:35:10下载
- 积分：1
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Cpp1
校园导游，可以选择景点序号来了解景点，通过选择两点可计算最短距离和最近路线。(Campus tour guide, you can choose the attractions serial number to understand the attractions of by selecting the shortest distance can be calculated and the recently routes.)
- 2012-06-20 21:57:32下载
- 积分：1
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InserSigList
单链表的插入。数据结构中的算法小程序。初学者很适用。(Single-linked list insertion. Data structure of algorithm applet. Beginners are applicable.)
- 2016-02-18 15:09:12下载
- 积分：1
