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YTY_GA_Final

于 2010-12-27 发布 文件大小:2KB
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   To find the largest fitness value and its location 寻找最大适应性及相应的位置! Population N=50;crossover bits=n/2 (half of bits of an individual) with random locations,mutation bits = 4 种群数 N=50,交换位数= n/2, 即个体位数的一半,且位置随机; 变异位数统一取为4; Nc=20,28,36,44,individuals for crossover(交换的个数)。 Nm=1,5,10,15, individuals for mutation(变异的个数)。 (To find the largest fitness value and its location to find the location of the maximum adaptability and the corresponding! Population N = 50 crossover bits = n/2 (half of bits of an individual) with random locations, mutation bits = 4 population size N = 50, exchange digits = n/2, ie half of the median individual, and random position variation is taken as unity median 4 Nc = 20,28,36,44, individuals for crossover (exchange number). Nm = 1,5,10,15, individuals for mutation (the number of variations.))

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