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fuzzy
用模糊控制方式控制锅炉水位，用模糊控制方式控制锅炉水位(Using fuzzy control of boiler water level control with fuzzy control of boiler water level control)
- 2009-05-16 18:06:35下载
- 积分：1
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chap2_08_RELS
系统辨识，最小二乘法matlab仿真程序，非常实用(System identification, least squares matlab simulation program, very useful)
- 2010-06-28 16:36:04下载
- 积分：1
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MSA
仿射不变特征提取 多尺度自卷积方法。。。。。。。。。。。。。。。。。。。(The Multi-Scale Autoconvolution (MSA) method offers a novel way of approaching this problem. The method provides affine invariant features with only moderate computational complexity and does not require any other segmentation steps than background elimination.)
- 2010-05-21 13:41:07下载
- 积分：1
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机械手的自适应滑模控制
机械手的自适应滑模控制matlab仿真程序，完整高效运行(Self-adaptive sliding mode control matlab simulation program, complete and efficient operation)
- 2018-03-29 09:42:35下载
- 积分：1
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Hurst
One way to determinate the Hurst exponent
- 2011-09-23 22:36:52下载
- 积分：1
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myself
capon波束形成及功率谱估计,一个目标信号加两个干扰(capon beamforming and power spectrum estimation, a target signal interference plus two)
- 2016-07-18 16:50:40下载
- 积分：1
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Denoise_wavelet_Mod
小波模极大值去噪，Denoise_w_Mod_sim.m是主程序，P_gama.m，P_y.m，Py_Pgama.m是三种投影算法(Wavelet modulus maxima denoising, Denoise_w_Mod_sim.m is the main program, P_gama.m, P_y.m, Py_Pgama.m are three projection algorithm)
- 2021-04-28 11:58:44下载
- 积分：1
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Leach
现成的——leach协议剩余节点和时间关系的awk脚本(Ready-made- leach agreement between the remaining nodes and the time awk script)
- 2010-12-03 15:36:00下载
- 积分：1
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Chapter6
数值解法
例1 用改进的欧拉方法求一阶方程初值问题的
数值解
例2 数学摆的运动方程与近似方程数值解比较
例3 四阶龙格库塔公式求数值解
Matlab实现求数值解
例1 求初值问题y =x*sin(x)-y,y(0)=0的数值
解.先编辑一个定义方程的ODEF函数文件
ODEfun1.m.
例2 求方程组初值问题的数值解,按指定步长
0.05划分节点.
例3 按指定的精度求高阶方程初值问题的数值解.(Numerical Solution of the law a method of using the improved Euler' s equation of order to a first-order initial value problem of the numerical solution of cases of two mathematical pendulum equations of motion compared with the approximate numerical solutions of equations of three cases of fourth-order Runge-Kutta numerical solution of the formula Matlab order to achieve the numerical solution of demand cases seeking an initial value problem y ' = x* sin (x)-y, y (0) = 0 the numerical solution. first, the definition of an equation editor ODEF function file ODEfun1.m. cases of two demand equations initial value problem of numerical solution, according to the specified division of the node step 0.05. Example 3 according to the specified precision of seeking higher-order equation of the numerical solution of initial value problem.)
- 2010-02-05 23:14:41下载
- 积分：1
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iFixInduction
说明： ifix入门资料，组态软件的学习好资料，通俗易懂，内容翔实！(ifix introductory information, learning good information configuration software, user-friendly and informative!)
- 2010-03-31 20:45:50下载
- 积分：1
