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adms

于 2012-06-09 发布 文件大小:3766KB
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下载积分: 1 下载次数: 17

代码说明:

  阿当姆斯显式和隐式求解方法,用四阶龙格库塔作为起始,然后运用四阶阿当姆斯算法求解初值问题。主要程序包含在test2.cpp中,方法简单易懂。编译环境VC2010(Adam James explicit and implicit method for solving fourth-order Runge-Kutta as a start, then use the fourth-order A Williams algorithm for solving initial value problem. The main program contains in test2.cpp method is simple and easy to understand. Compile environment VC2010)

文件列表:

adms
....\adms
....\....\adms.vcxproj,3915,2012-06-06
....\....\adms.vcxproj.filters,943,2012-06-06
....\....\adms.vcxproj.user,143,2012-06-06
....\....\Debug
....\....\.....\adms.exe.embed.manifest,406,2012-06-06
....\....\.....\adms.exe.embed.manifest.res,472,2012-06-06
....\....\.....\adms.exe.intermediate.manifest,381,2012-06-06
....\....\.....\adms.lastbuildstate,48,2012-06-06
....\....\.....\adms.log,2204,2012-06-06
....\....\.....\adms_manifest.rc,198,2012-06-06
....\....\.....\CL.read.1.tlog,9654,2012-06-06
....\....\.....\CL.write.1.tlog,214,2012-06-06
....\....\.....\link-cvtres.read.1.tlog,2,2012-06-06
....\....\.....\link-cvtres.write.1.tlog,2,2012-06-06
....\....\.....\link.5876-cvtres.read.1.tlog,2,2012-06-06
....\....\.....\link.5876-cvtres.write.1.tlog,2,2012-06-06
....\....\.....\link.5876.read.1.tlog,2,2012-06-06
....\....\.....\link.5876.write.1.tlog,2,2012-06-06
....\....\.....\link.read.1.tlog,2562,2012-06-06
....\....\.....\link.write.1.tlog,488,2012-06-06
....\....\.....\mt.read.1.tlog,222,2012-06-06
....\....\.....\mt.write.1.tlog,222,2012-06-06
....\....\.....\rc.read.1.tlog,194,2012-06-06
....\....\.....\rc.write.1.tlog,202,2012-06-06
....\....\.....\test2.obj,62641,2012-06-06
....\....\.....\vc100.idb,232448,2012-06-06
....\....\.....\vc100.pdb,266240,2012-06-06
....\....\test2.cpp,1407,2012-06-06
....\adms.sdf,6639616,2012-06-06
....\adms.sln,879,2012-06-06
....\Debug
....\.....\adms.exe,43008,2012-06-06
....\.....\adms.ilk,535068,2012-06-06
....\.....\adms.pdb,691200,2012-06-06
....\ipch
....\....\adms-feaaced4
....\....\.............\adms-4046af71.ipch,15269888,2012-06-06

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