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zhoucheng
轴承故障诊断，经验模态分解，采用切片双谱(Bearing fault diagnosis, empirical mode decomposition, using slices bispectral)
- 2013-05-27 23:59:03下载
- 积分：1
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Matlab
Matlab codes for descriptors
- 2014-01-28 18:01:26下载
- 积分：1
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MIMLBoost
matlab编写的MIMLBoosting算法，其中包括实现算法的函数，还有可作为示例的数据和主程序，可以运行，可以对多示例多标记样本进行分类，并计算正确率等多个指标。(MIMLBoosting algorithm matlab prepared, including the implementation of the function of the algorithm, as well as examples of data and the main program, you can run, you can multi-instance multi-label classification of samples and calculate the number of indicators, such as the correct rate.)
- 2014-01-15 15:12:17下载
- 积分：1
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9-10
自适应滤波原理（国外教材）计算机作业的MATLAB程序，调试通过，有一定的参考价值。(Principles of Adaptive Filtering (foreign materials) MATLAB computer operating procedures, testing is passed, there is a certain reference value.)
- 2009-06-07 14:38:20下载
- 积分：1
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Sonhiz
this program include successfull matlab code
- 2011-04-29 20:55:41下载
- 积分：1
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eee
杨氏双缝干涉
两相干光源到接收屏上P点距离r1=(D2+(y-a/2)2)1/2, r2=(D2+(y+a/2)2)1/2,
满足相干条件的光波叠加后，对于观察屏上某一确定点，即r1、r2确定后，叠加后的光强为 式中λ为光波的波长， 、 ，令相位差φ=2π（r2-r1）/λ,
最后可得公式如下：
，
最后光强I=4I0cos2（Φ/2）。
观察相干光叠加后光强的分布.
(Young' s double slit interference two coherent light source to the point P on the receiving screen distance r1 = (D2+ (YA/2) 2) 1/2, r2 = (D2+ (y+a/2) 2) 1/2, meet coherent conditions lightwave after superposition, for a determined point on the viewing screen, i.e. R1, R2 is determined, the superimposed light intensity where λ is the wavelength of light, make the phase difference φ = 2π (R2-R1)/λ, final can be obtained using the following formula: Finally, the light intensity I = 4I0cos2 (φ/2). Observed coherent superposition of light intensity distribution.)
- 2013-01-03 21:04:13下载
- 积分：1
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62(A-spectral-clustering-algorithm-based-on-intui
a spectral clustering algorithm based on fuzzy information
- 2015-04-13 14:38:12下载
- 积分：1
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Morth
Probability of symbol and bit error for M orthogonal signals
- 2008-01-14 15:47:16下载
- 积分：1
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1001-3695(2013)02-0613-03
基于Bayesian压缩感知的融合算法.pdf(Image fusion algorithm based on bayesian compressive sensing)
- 2014-02-02 08:02:43下载
- 积分：1
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3zuoye
某市有一码头，每次仅容一辆船停泊装卸货，由于经常有船等候进港，部分人提出要扩建码头。经过调查历史资料发现，码头平均每月停船24艘，每艘船的停泊时间为24±20小时，相邻两艘船的到达时间间隔为30±15小时，如果一艘船因有船在港而等候1小时，其消耗成本为1000元。经预算，扩建码头大约需要1350万元，故市长决策如下：如果未来五年内停泊船只因等候的成本消耗总和超过扩建码头花费则扩建码头，否则，不予扩建。因此，希望你能够帮助市长做出决策。此问题已知到达的大概时间和大概停泊时间，对于此问题用概率统计的方法来做比较复杂，可用程序随机产生到达时间和停泊时间来模拟未来五年内船的停泊，多次模拟预测停泊情况，以做出决策(。-Problem in a city with a terminal expansion dock, each only allow a boat moored loading and unloading, as often there are waiting boat into port, some people proposed to expand pier. Terminal stopping 24 per month, per vessel berthing time of 24 ± 20 hours, the arrival of two adjacent vessels interval 30 ± 15 hours, if a ship due to boat in the harbor while waiting for one hour, and its consumption cost of 1,000 yuan. The budget of about 13.5 million yuan expansion dock, so the mayor decision as follows: If a ship is moored next five years, the cost of waiting more than the sum of consumption spending is expanding marina pier extension, otherwise, not expanded.)
- 2015-04-17 18:59:46下载
- 积分：1
