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b
说明： 定义一个类SortArray继承自MyArray，在该类中定义函数sort实现排序功能。
定义一个类ReArray继承自MyArray，在该类中定义函数reverse实现逆转功能。
定义一个类AverArray继承自MyArray，在该类中定义函数Aver实现求解整数的平均值。
定义NewArray类，同时继承了SortArray、ReArray和AverArray，使得NewArray类的对象同时具有排序、逆转和求平均值的功能。在继承的过程中声明为虚基类，体会虚基类在解决二义性问题中的作用。
(Define a class SortArray inherited from MyArray, defined in the class sorting function sort implementation. Define a class ReArray inherited from MyArray, define the function in reverse to achieve such reversal function. Define a class AverArray inherited from MyArray, defined in the class to solve integer function Aver achieve the average. Defined NewArray class, and inherits SortArray, ReArray and AverArray, making the object of both NewArray class sorting, reversing, and the mean value of the function. In the process of succession declared as virtual base classes, virtual base class experience in resolving ambiguities of the role.)
- 2010-06-02 02:13:03下载
- 积分：1
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lvxingshang
一个经典的旅行商问题源码，不是最优解，只是一种 思路(A classic traveling salesman problem source is not the optimal solution, just a thought)
- 2012-11-09 01:33:02下载
- 积分：1
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data_structure
数据结构c源代码实现，大概有100个左右，基本上将所有的数据结构都有介绍(Data structures c source code to achieve, there are about 100 or so, basically all of the data structures are described)
- 2012-07-19 21:43:52下载
- 积分：1
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BFS
迷宫问题 队列求解 界面还不完善 可以自己添加(Maze problem solving interface queue is not perfect you can add your own)
- 2013-12-26 22:08:58下载
- 积分：1
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yinhangmoni
这是一个简单的银行模拟系统
1、 客户的到达时间随机
2、 客户需要处理的业务随机（不同业务处理的平均长度不同，例如：取款时间较短，开户和销户时间较长）
3、 处理客户业务所需时间随机（在一定范围内）
4、 使用文本文件记录每个客户到达时间、业务处理时间、业务结束时间
5、 动态显示（刷新时间可调）目前每个窗口累计处理客户数量、等待人数，每个窗口的平均业务处理时间，不同业务类型业务的累计办理量。
(This is a simple bank simulation system
1 customer arrival time random
2, customers need to deal with the business of random (the average length of the different business processes, such as: the withdrawal shorter, longer to open an account and cancel the account)
3, the time required to deal with customer service random (within certain limits)
4, using a text file to record each customer arrival time, business processing time, the business end of time
5 dynamically display (refresh time is adjustable) each window is accumulated to handle the number of customers waiting for the number the average business processing time of each window, different type of business operations total for the amount.)
- 2012-11-22 00:08:18下载
- 积分：1
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list-and-array
数组的定义与使用，数组的运算，字符串的输入与输出，冒泡排序(list and array)
- 2013-10-17 11:32:30下载
- 积分：1
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pinfanfangwen
设有一头指针为L的带有表头结点的非循环双向链表，其每个结点中除有prev（前驱指针），data（数据）和next（后继指针）域外，还有一个访问频度域freq。在链表被起用前，其值均初始化为零。每当在链表中进行一次Locate(L,x)运算时，令元素值为x的结点中freq域的值增1，并使此链表中结点保持按访问频度非增（递减）的顺序排列，同时最近访问的结点排在频度相同的结点的最后，以便使频繁访问的结点总是靠近表头。试编写符合上述要求的Locate(L,x)运算的算法，该运算为函数过程，返回找到结点的地址，类型为指针型。(Has a head pointer is non-circular doubly linked list L with a header node, each node in addition to prev (precursor pointer), data (data) and next (successor pointers) outside, there is an access frequency degree domain freq. Before the list was hired, their values are initialized to zero. Whenever carried out in the list once Locate (L, x) when the operation, so that the element node x is the value in freq domain by one, and keep this list in the node-access frequency of non-increasing (decreasing) the order, while a recent visit to the nodes in the same row of the frequency of the last node, so that the nodes are frequently accessed tables are always near the head. Locate (L, x) algorithm is prepared in accordance with the above requirements of the test operation, the operation as a function of the process, return to find the address of the node of type pointer.)
- 2015-01-15 22:31:59下载
- 积分：1
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Kruskal
采用Kruskal算法求最小生成树主要数据结构
edgeset GE 存放图中的所有边
int n,int e 存放图中的顶点数与边数
edgeset C 存放生成树中的边
vexlist gv 图中结点的顶点值
adjmatrix s 用来处理图中结点的查找与合并
int m1,m2 一条边上两顶点所属集合的序号
int k 最小生成树中的边数
int d //图中待扫描边元素的下标(For the Minimum Spanning Tree by Kruskal main data structures edgeset GE store all edges in the figure int n, int e store graph vertices and edges edgeset C storage spanning tree edges in the vexlist gv graph node vertex values adjmatrix s used to process graph node to find and merge int m1, m2 an edge belongs to the set number two vertices int k minimum spanning tree edges int d // figure to be Scan edge element subscript)
- 2011-05-17 10:22:56下载
- 积分：1
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delete
数据结构 实验练习 删除相同的节点 希望会对大家有所帮助(Data structures lab exercises to remove the same node want to be helpful to everyone)
- 2012-11-14 12:59:15下载
- 积分：1
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Joseph
说明： 约瑟夫问题，四种解法，分别是静态链表，顺序表两种和循环链表(Joseph problems, the four solution, namely a static list, order form and the cycle of two lists)
- 2010-04-23 08:20:53下载
- 积分：1
