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Czhihen
关于C语言的一些指针的处理算法，能够使得初学者对C语言指针有自己的了解(Some pointers on C language processing algorithms, it is possible to make a beginner C language pointer has its own understanding)
- 2016-06-17 11:29:59下载
- 积分：1
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PRIM
PRIM算法 对任意给定的网和起点，用PRIM算法的基本思想求解出所有的最小生成树。(PRIM algorithm for any given network and the starting point, PRIM algorithm used to solve the basic idea of all the minimum spanning tree.)
- 2009-01-11 19:05:21下载
- 积分：1
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DoubleStack
数据结构基础内容，两栈共享空间，参考《大话数据结构》(Structural basis of data content, two stacks shared space, refer to Westward data structure )
- 2014-12-06 12:09:30下载
- 积分：1
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Huffman-Tree
使用三叉链表实现的哈夫曼树,统计inputfile1.txt中各字符的出现频率，并据此构造Huffman树，编制Huffman 码；根据已经得到的编码，对01形式的编码段进行译码。
具体的要求：
1．将给定字符文件编码，生成编码，输出每个字符出现的次数和编码；
2．将给定编码文件译码，生成字符，输出编码及其对应字符。
(Emergence of the frequency of each character in the trigeminal lists using the Huffman tree, statistics inputfile1.txt, and accordingly the Huffman tree structure, preparation of Huffman code according to the coding has been. 01 to form the code segment for decoding.
Specific requirements:
1 coding the given character file, generating the encoding, and outputting the number and encoding of each character
2 will be given the encoding file decoding, generating the character, the output code and its corresponding character.)
- 2015-05-22 15:37:03下载
- 积分：1
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2
说明： 用数据结构的遍历，对于小毛驴过河解决实际问题。(Traversing the data structure used for the small donkey across the river to solve practical problems.)
- 2010-06-02 22:50:30下载
- 积分：1
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SHU
为了点分 求分下载好麻烦 c++二叉排序树(In order to find points dotted download good trouble c++ binary sort tree)
- 2013-07-25 01:35:56下载
- 积分：1
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chain
链表的模板类,提供插入删除，遍历器，查找等功能，只有一个头文件，可以包含到你的工程(template implemention of Chain)
- 2013-12-09 11:04:33下载
- 积分：1
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migong
迷宫算法，1代表可以通过，0代表墙壁，自动找寻路线(Maze algorithm, 1 can pass 0 for the walls, automatically find routes)
- 2011-06-11 17:13:39下载
- 积分：1
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Ex1
从屏幕输入字符 判断括号匹配问题 数据结构作业(Judgment parenthesis matching data structure operations input characters from the screen)
- 2012-11-27 15:17:10下载
- 积分：1
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maze
迷宫求解一般采用“穷举法”，逐一沿顺时针方向查找相邻块（一共四块－东(右)、南(下)，西(左)、北(上)）是否可通，即该相邻块既是通道块，且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)
- 2013-12-13 17:55:45下载
- 积分：1
