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NSEA algorithm on a small program
关于NSEA算法的一个小程序-NSEA algorithm on a small program
- 2022-02-01 18:17:53下载
- 积分：1
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ECC加密Matlab实现
Matlab实现ECC加密的源码，可供ECC加密签名学习(The source code of ECC encryption implemented by MATLAB can be used for ECC encryption signature learning.)
- 2021-01-17 16:48:49下载
- 积分：1
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title=Windows NT/2000/XP 虚拟磁盘驱动程序 memo=将一个或多个文件模拟成物理磁盘。...
title=Windows NT/2000/XP 虚拟磁盘驱动程序 memo=将一个或多个文件模拟成物理磁盘。-title=Windows NT/2000/XP simulated disk drive
memo=let one or more file simulate a physical disk
- 2023-02-14 18:35:04下载
- 积分：1
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RSA C语言实现
用C语言实现的RSA算法，各个部分模块，都有详细介绍。密钥生成、大素数产生、素数判断、参数的选取，都有，用C语言实现的RSA算法。
- 2022-03-21 03:52:05下载
- 积分：1
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lattice_processor
C++ 实现格公钥密码, 包括LWE困难问题。(implementation of lattice public key cryptography)
- 2017-09-20 11:01:24下载
- 积分：1
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including registration generation software, LIB, DLL encryption modules in vario...
包括注册号生成软件、LIB、DLL 加密模块 各种语言调用加密模块的例子程序等-including registration generation software, LIB, DLL encryption modules in various languages called encryption module examples procedures
- 2022-01-25 23:56:34下载
- 积分：1
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find-the-secret
星号密码查看器，只需将放大镜置于要查看星号密码的上方，就能显示出原密码。(Asterisks password viewer, simply put a magnifying glass to view asterisk password above, can show the original password.)
- 2013-07-22 15:38:44下载
- 积分：1
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Base64 加密算法（Author 蒋柏良 Jerry Jiang)
Base64 加密算法（Author 蒋柏良 Jerry Jiang)-*
* DESCRIPTION
* Base64 processes input in 24bit chunks by converting each chunk into 4
* bytes of output. It does so by splitting input into four 6bit groups and
* using these as indexes in the following substitution table-
* const char base64_map[] =
* "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
* "abcdefghijklmnopqrstuvwxyz"
* "0123456789+/"
* If an input is not a multiple of 3 bytes, it s padded with zeros. In
* this case the output bytes that consist entirely of the pad data are
* replaced with = .
*
* Example
* An input of 0x00 0x45 0xF2 is equivalent to 00000000 01000101 11110010
* bit sequence, which s then split into 000000 000100 010111 110010
* and these are substituted to produce the following base64 encoding
* A E X y
*
* RETURN VALUE
* b64_length() should return output length for the input of len bytes.
* b64_encode() should encode len bytes from src int
- 2022-07-18 16:55:26下载
- 积分：1
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2的16次幂正整数d与n，编写计算d
2的16次幂正整数d与n，编写计算d-1 (mod n) 的程序；
2、对于三个不超过2的16次幂正整数a、e与n，编写计算ae (mod n) 的程序。
在上述程序基础上写出下列程序：
（1） 对给定的10000以内数判定其是否为素数；
（2） 进行ElGamal体制的加密与签名。
-two of 16 power-positive integer d and n, calculate the preparation of d-1 (mod n); 2. For not more than 2 3 16 Powers positive integers a, e and n, calculate the preparation ae (mod n) procedures. In the above procedure to write on the basis of the following procedures : (a) the right to 10,000 within a few judging whether a prime number; (2) ElGamal encryption and signature.
- 2022-02-14 21:21:03下载
- 积分：1
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crapto1
NXP智能卡 核心加密方法。 crapto1 crapto1 方法。(NXP smart card m1 crapto encryption method.
)
- 2011-12-25 13:19:33下载
- 积分：1
