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tspopf4.1_w32
MATLAB工具箱，进行电力系统分析，计算最优潮流(MATLAB toolbox, power system analysis, optimal power flow calculation)
- 2015-04-01 10:53:57下载
- 积分：1
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four-stepRunge-Kuttastatutoryfour-stepRunge-Kuttam
解微分方程（组）的定步长四阶龙格库塔法算法源代码(Solution of differential equations (Group) of fixed step size fourth-order Runge-Kutta method algorithm source code)
- 2020-07-15 19:18:50下载
- 积分：1
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gridon01
说明： 采用LCL滤波器的并网逆变器双闭环控制系统仿真,系统采用电感电流外环电容电流内环(The double closed-loop control system of grid-connected inverter with LCL filter is simulated. The system adopts inductance current outer loop and capacitance current inner loop.)
- 2019-04-23 15:59:59下载
- 积分：1
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mtkaihuan
主要设计了在matlab下异步电动机在mt坐标轴下的开环控制仿真。(The main design of the asynchronous motor in matlab mt axis open-loop control simulation.)
- 2012-05-04 10:47:13下载
- 积分：1
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matlab4
说明： 基于小波的人脸识别算法的matlab实现(Face Recognition Based on Wavelet matlab algorithm to achieve)
- 2008-10-17 10:20:07下载
- 积分：1
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gailv
matlab 概率统计技术，适合初学者学习(matlab probability and statistics techniques suitable for beginners to learn)
- 2010-06-20 12:48:10下载
- 积分：1
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hegseg
这是一个关于多目标数据融合的很好的温章，希望对大家有所帮助。原理清晰，见解独特(This is a multi-target data fusion on the temperature of a good chapter, we want to help. Principle of clear, maverick)
- 2010-02-26 16:41:01下载
- 积分：1
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Diffusion-system-of-concentration-
扩散系统之浓度分布的装置。管中储放静止液体B，高度为L=10 ㎝，放置于充满A 气体的
环境中。假设与B 液体接触面之浓度为3
C 0 0.01mol m A = ，且此浓度不随时间改变
而改变，即在操作时间内( h = 10天)维持定值。气体A 在液体B 中之扩散系数为
D m s AB
= 2×10− 9 2 。试决定以下两种情况下，气体A溶于液体B中之流通量(flux)。
(a) A 与B 不发生反应；
(b) A 与B 发生以下之反应
A+ B→C ， A A − r = kC
其反应速率常数k = 2×10− 7 s− 1。
(Diffusion system of concentration reference device shown in Figure 3. Tube in the store still liquid B, L = 10 cm height, placed in full A gas environment. Assuming the contact surface of the liquid with the B concentration of 3 C 0 0.01mol m A =, and this concentration does not change with time and change, that is, the operating time (h = 10 days) to maintain constant. Gas A in liquid B, the diffusion coefficient D ms AB = 2 × 10-9 2. Decided the following two test cases, the gas dissolved in liquid B in the A liquid (flux). (A) A and B do not react (b) A and B of the following reaction occurs A+ B → C, AA- r = kC, the reaction rate constant k = 2 × 10-7 s-1.)
- 2011-08-30 22:26:43下载
- 积分：1
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C
说明： 1.1 C基础知识 1
1.2 函数与头文件 2
1.3 C预处理器 3
1.4 将一个字符转换为long型 4
1.5 strcpy函数 4
1.6 assert用法 5
1.7 itoa函数和atoi函数 6
1.8 strcmp函数实现 8
1.9 strcpy函数实现 9
1.10 memcpy函数实现 10
1.11 memcpy和memmove函数的实现 11
1.12 strcat函数实现 13
1.13 使用库函数atoi，将char *→int 13
1.14 使用库函数itoa，将int→char * 14
1.15 不使用库函数，将int→char * 14
1.16 不使用库函数，将char *→int 15
1.17 求两个整数的最大公约数 16
1.18 Little_endian or Big_endian 17
1.19 sizeof与strlen的区别 19
1.20 实现String类的BIG_FOUR 19
1.21 struct和union的区别 20
1.22 char字符变量与int整型数据 22
1.23 字,字节,字符,比特 23
1.24 空格、空字符、字符数组结束符的区别 25(1.1 C Basics 1
1.2 Functions and header files 2
1.3 C preprocessor 3
1.4 will be a long-type characters into four
1.5 strcpy function 4
1.6 assert usage 5
1.7 itoa function and atoi function 6
1.8 strcmp function to achieve 8
1.9 strcpy function to achieve 9
1.10 memcpy function to achieve 10
Achieve 11 1.11 memcpy and memmove function
1.12 strcat function to achieve 13
1.13 using the library function atoi, the char* → int 13
1.14 using the library function itoa, the int → char* 14
1.15 does not use the library function, int → char* 14
1.16 does not use the library function, char* → int 15
1.17 find the greatest common divisor of two integers 16
1.18 Little_endian or Big_endian 17
Difference 1.19 sizeof and strlen 19
1.20 realize BIG_FOUR String class 19
Difference 1.21 struct and union of 20
1.22 char and int integer variable character data 22
1.23 word, byte, character, bit 23
Difference 1.24 spaces, null characters, character array termi)
- 2014-10-08 10:33:55下载
- 积分：1
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Simulink_rus
similunk book about rus for advanced simulation and modeling
- 2013-10-07 16:42:12下载
- 积分：1
