登录
首页 » matlab » ratewaterfillingbasedonofdm

ratewaterfillingbasedonofdm

于 2009-12-12 发布 文件大小:2KB
0 111
下载积分: 1 下载次数: 52

代码说明:

  这个程序实现了ofdm下的注水原理,是一个基于速率的注水程序,并不是传统的基于功率的注水原理。(This program realise a program based on waterfilling method which is concerning the rate adaptation not the power adaptation.)

文件列表:

ratewaterfilling.m

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • volumemesh1
    VOLUMEMESH1 Creates "open" volume metal meshes and their modificitations
    2010-06-21 07:31:36下载
    积分:1
  • slider_crank
    Mechanism Design Slider crank Mechanism
    2009-05-11 11:30:12下载
    积分:1
  • Introduction-to-Random-Signals-and-Applied-Kalman
    Introduction to Random Signals and Applied Kalman Filtering
    2014-09-01 17:35:35下载
    积分:1
  • vunv1
    these files are related to speech processing and adaptive filtering
    2013-08-21 16:16:13下载
    积分:1
  • MATLAB
    MATLAB命令大全,MATLAB命令大全word文档(MATLAB)
    2009-12-11 17:03:43下载
    积分:1
  • MATLAB-7
    MATLAB 7 界面设计与编译技巧,适合初学者,详细地介绍了如何进行matlab GUI的设计(MATLAB 7 interface design and compilation techniques, suitable for beginners, detailed description of how the design of matlab GUI)
    2011-05-13 10:40:12下载
    积分:1
  • Matlab-GUI
    在matlab编译环境下对用户界面的编译快速入门教程,对于matlab初学者比较有帮助。(In the matlab compiler environment of the user interface compiler Quick Start Guide, more helpful for matlab beginners.)
    2011-05-26 18:18:48下载
    积分:1
  • GeodesicActiveContour
    Geodesic active contour
    2007-03-03 01:05:29下载
    积分:1
  • EKF_UKF_PF
    EKF_UKF_PF三种算法的比较,仿真结果很明显。(EKF_UKF_PF comparison of three algorithms, simulation results are obvious.)
    2013-08-10 16:24:08下载
    积分:1
  • pi_method1
    Estimated number of Pi ( Method 1) how do we estimate Pi by simulation? In the simulation, you keep throwing darts at random onto the dartboard. All of the darts fall within the square, but not all of them fall within the circle. Here s the key. If you throw darts completely at random, this experiment estimate the ratio of the area of the circle to the area of the square, by counting the number of darts in each. Our study of the geometry tells us this ratio is Pi/4. So, now we can estimate Pi as
    2013-04-29 02:49:47下载
    积分:1
  • 696518资源总数
  • 104432会员总数
  • 16今日下载