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MM1
基于matalbd 排队possion mm1 模拟(Simulation based matalbd line possion mm1)
- 2010-12-19 19:44:52下载
- 积分：1
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Target-Tracking-with-UKF
说明： 应用无迹卡尔曼滤波较好的实现单目标跟踪。(Unscented Kalman filter applied to achieve good single-target tracking.)
- 2011-02-18 10:29:05下载
- 积分：1
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ThrSample2
自然三次样条几乎等同于样条设备生成的曲线。在这些所有的二次连续可导函数中，钳位与自然三次样条可以得到相对于待插值函数 f 的最小值(spline interpolation)
- 2012-04-26 21:59:27下载
- 积分：1
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montecarlo
蒙的卡罗法的源代码，用于随机过程的编码，是我们老师编的(By Saul the source code card method for random process coding, is made of our teacher)
- 2011-12-13 21:13:50下载
- 积分：1
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omp
基于matlab仿真平台,快速匹配追踪OMP算法的图像稀疏分解与重构,并附带有OMP算法的详细讲解PPT(Based on the simulation platform of MATLAB, the fast matching pursuit (OMP) algorithm for image sparse decomposition and reconstruction. And with the OMP algorithm explained in detail PPT.)
- 2015-04-08 12:11:13下载
- 积分：1
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R
说明： 正交试验方差分析在matlab上的运行方法，是学习matlab的一个重要步骤，直接解压运行(Orthogonal method of analysis of variance run in matlab, is an important step in learning matlab direct decompression operation)
- 2013-12-02 10:27:38下载
- 积分：1
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Boost_Converter
说明： 升压转换器是一种DC / DC电源转换器，可将电压从其输入（源）升至其输出（负载）。在连续导通模式下（流经电感的电流永远不会降为零），升压转换器的理论传递函数为：
占空比在哪里0.5
在此示例中，转换器从250 V电源馈送RC负载，并且PWM频率设置为31 kHz。
模拟
运行仿真并观察示波器上的波形。确认负载电压（Vout）的平均值非常接近理论值：Vout = 250 /（1- 0.5）= 500V。(A boost converter is a DC/DC power converter which steps up voltage from its input (source) to its output (load). In continuous conduction mode (current through the inductor never falls to zero), the theoretical transfer function of the boost converter is:
where is the duty cycle.0.5
In this example, the converter is feeding an RC load from a 250 V source and the PWM frequency is set to 31 kHz.
Simulation
Run the simulation and observe waveforms on Scope. Verify that the mean value of the load voltage (Vout) is very close to the theoretical value of: Vout = 250 / (1 - 0.5) = 500 V.)
- 2020-03-22 20:41:56下载
- 积分：1
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signal_analyzer
用Matlab来进行信号分析。源码及说明都有。(Carried out using Matlab signal analysis. Both source and description.)
- 2009-10-09 12:09:33下载
- 积分：1
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yingyong
matlab开发学生成绩管理，比较有启发性。(the development of student achievement management matlab)
- 2009-05-21 20:06:37下载
- 积分：1
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bianhuan
对给定图像裁剪为384×384，对其分别进行傅立叶等变换 。。。——bianhuan.m(For a given image cut to 384 × 384, so its Fourier transform respectively. . .- Bianhuan. M)
- 2010-07-19 10:21:49下载
- 积分：1
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