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encode_bit

于 2009-11-24 发布文件大小:3KB

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关于turbo码编码的仿真程序，简单实用，是初学者的理想程序(On the turbo coding of the simulation program, simple and practical, is the ideal program for beginners)

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2D
说明： Riemann integral. Adaptative method, 2D

2009-10-28 07:19:20下载

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untitled
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RVM
关联向量机的硕士博士论文，关联向量机是支持向量机的发展，开发工具主要是matlab(Associated with the master s thesis vector machines, relevance vector machine is the development of support vector machines, development tools, mainly matlab )

2012-01-10 12:12:00下载

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cpofdm
基于子空间的盲信道估计算法，用的是奇异值的分解Subspace-based blind channel estimation algorithm, using a singular value decomposition (Subspace-based blind channel estimation algorithm, using a singular value decomposition )

2010-09-14 22:35:13下载

积分：1
simulink_labs
Matlab examples for practice.

2009-04-19 06:31:32下载

积分：1
myfdr
matlab仿真出刀刃的夫琅禾费衍射，其中有四副图，原图，二维衍射图样，函数图象和三维衍射图样(matlab simulation of the cutting edge of the Fraunhofer diffraction, which has four maps, original, two-dimensional diffraction patterns, functions, images and three-dimensional diffraction pattern)

2011-05-15 16:36:28下载

积分：1
ybus
computation of ybus in ieee 39 bus

2011-06-18 00:52:47下载

积分：1
Kjunzhijulei
使用k均值算法对多个数据集进行分类，已测试通过，简单易懂(classification to many datasets using k-means algorithm ,simple and easy-understanding.)

2013-11-09 01:18:48下载

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one
产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)

2013-11-26 16:24:18下载

积分：1

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encode_bit

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