Have n integers, the number of its previous order backward shift position m, and...
于 2023-07-26 发布
文件大小:2.64 kB
0 62
下载积分: 2
下载次数: 1
代码说明:
有n个整数,使其前面各数顺序向后移m个位置,最后m个数变成最前面的m个数.-Have n integers, the number of its previous order backward shift position m, and finally the number m of m into the first number.
下载说明:请别用迅雷下载,失败请重下,重下不扣分!
发表评论