-
此教程面对JSP初学者而写，为提高正确性和按本教程操作必定成功的机率，作者我是一边安装操作一边抓图一边写的，并进行过仔细的检查，当然，人有失手，若其中有错，那么...
此教程面对JSP初学者而写，为提高正确性和按本教程操作必定成功的机率，作者我是一边安装操作一边抓图一边写的，并进行过仔细的检查，当然，人有失手，若其中有错，那么是上天注定的了，与作者无关^_^。 在理论上来讲，只要你一步不漏并正确按本教程安装配置JSP环境，那么你的成功率是120％。 若果还是无法成功，你可以联系作者或Delete本教程，若本教程给你造成困绕本人深感抱歉！-face JSP beginners writing, and to improve accuracy by the Guide will operate the chances of success, the writer side of me is the installation operation side of the screen in the side was made and carried out a detailed inspection and, of course, people have missed, and if there is something wrong, then God is predestined, with the author unrelated ^ _ ^. In theory, as long as you do not step on the right and missed the handbook installation configuration JSP environment, then your success rate is 120%. If successful or not, you can contact the author of the handbook or Delete, if the Guide to haunt you cause I am deeply sorry!
- 2022-02-06 14:08:12下载
- 积分：1
-
This a JPEG encoding & decoding program of still image. It does not use level sh...
This a JPEG encoding & decoding program of still image. It does not use level shifting. Discrete Cosine transform (DCT) is performed both by classical & Chen s Flowgraph methods. Predefined JPEG quantization array & zigzag order are used here. RUN - LEVEL coding is used instead of Huffman coding. Compression ratio is compared for each DCT method. Effect of coarse and fine quantization is also examined. The execution time of 2 DCT methods is also checked. In addition, most energatic DCT coefficients are also applied to examine the effect in MatLab 7.4.0 R2007a. Input is 9 gray scale pictures & output is 9*9=81 pictures to compare. Blocking effect is obvious.
-This is a JPEG encoding & decoding program of still image. It does not use level shifting. Discrete Cosine transform (DCT) is performed both by classical & Chen s Flowgraph methods. Predefined JPEG quantization array & zigzag order are used here. RUN - LEVEL coding is used instead of Huffman coding. Compression ratio is compar
- 2022-12-20 21:45:04下载
- 积分：1
-
学习英语形象记忆法
学习英语形象记忆法-learning English mnemonic image
- 2022-05-24 07:05:10下载
- 积分：1
-
精通matlab6.5 (北航 张志涌),绝对的好书
精通matlab6.5 (北航 张志涌),绝对的好书-Proficient matlab6.5 (BUAA Zhang Yong), the absolute good
- 2022-03-22 02:52:54下载
- 积分：1
-
本书回答了大部分基本的XML问题―什么是XML，为什么需要它，以及怎样使用它―并且介绍了到目前为止最重要、最实用的XML技术。...
本书回答了大部分基本的XML问题―什么是XML，为什么需要它，以及怎样使用它―并且介绍了到目前为止最重要、最实用的XML技术。-the book to answer the most basic question of XML-What is XML, why need it, and how to use it- and so far introduced the most important and practical XML technology.
- 2022-01-31 01:26:21下载
- 积分：1
-
nstallShield for Microsoft Visual C＋＋ 6 是一个非常好的制作安装程序的软件...
nstallShield for Microsoft Visual C＋＋ 6 是一个非常好的制作安装程序的软件-vc basic nstallShield for Microsoft Visual C＋＋ 6
- 2022-03-01 13:17:36下载
- 积分：1
-
现在学习ENVI的人很多，现在提供ENVI培训讲义
现在学习ENVI的人很多，现在提供ENVI培训讲义-ENVI is now learning a lot of people, now offers training handouts ENVI
- 2023-01-20 13:40:05下载
- 积分：1
-
舞伴问题假定在一舞会上，男士排成一队，女士排成一队。跳舞开始时，依次从男队和女队的队头各出一人配成舞伴。若两队初始人数不相同，则较长的那一队中未配对者等待下一轮...
舞伴问题假定在一舞会上，男士排成一队，女士排成一队。跳舞开始时，依次从男队和女队的队头各出一人配成舞伴。若两队初始人数不相同，则较长的那一队中未配对者等待下一轮舞曲。设计要求：模拟上述舞伴系统，并能计算对于任何男士A和女士B在哪一轮舞曲中的k次跳舞？ -Question assumes that a dance partner, the men line up a team, ladies and line up a team. Dancing began, followed by men" s and women" s team from the team dubbed the first one from each partner. If the initial number of teams is not the same, then the longer of that team who is not waiting for the next round of the dance pairs. Design requirements: Analog the partner system, and can calculate for any men" s A and women dance in B in which a k-dance?
- 2022-03-09 22:16:12下载
- 积分：1
-
关于OpenMP性能调优的资料，更深一步学习如何提高程序性能。主要掌握了循环互换，循环展开和循环合并等方法，和缓存的一致性来解决共享变量带来的负荷，了解了线性递...
关于OpenMP性能调优的资料，更深一步学习如何提高程序性能。主要掌握了循环互换，循环展开和循环合并等方法，和缓存的一致性来解决共享变量带来的负荷，了解了线性递推（Linear Recurrence）和如何用分块提高矩阵的更新效率。
-On the OpenMP performance tuning information, deeper to learn how to improve program performance. Main mastered the loop interchange, loop start and loop merging and so on, and cache consistency to solve the shared variables to bring the load to find the linear recurrence (Linear Recurrence), and how to block updates to improve the efficiency of the matrix.
- 2022-01-25 21:47:31下载
- 积分：1
-
ewrfewr ewr e
ewrfewr e-ewrfewr ewr e
- 2022-07-03 14:10:25下载
- 积分：1
