ccna的学习笔记，有一定的学习价值，Cisco 网路设备之设定与管理-the study notes that there is a definite learning value, the Cisco network equipment and management set

赛灵思的如何撰写测试平台的挺好的文档，不过是英文的-Xilinx

apache2中文使用手册-apache2 Chinese Manuals

VisualC++程序设计从入门到精通 程序源代码-VisualC++ program design from entry into the master source code

Getting Started with JBoss 4.0 Release 5 The goal of this book is to get you up and running J2EE 1.4 applications on JBoss 4.0 as quickly as possible.-Getting Started with JBoss 4.0 Release 5 Th e goal of this book is to get you up and running J2E E 1.4 applications on JBoss 4.0 as quickly as pos sible.

程序员入门与游戏编程经验谈，对于想要开发游戏的朋友可以看看。-entry programmers and game programming experience, developing games for want of a friend can look at.

非线性光学原理 上(沈元壤)：同学赠送的、很难找的非线性光学书籍，-On nonlinear optics (Shen Yuan soil): Students donated, it is difficult to find books on nonlinear optics,

《Microsoft Visual C++.NET技术内幕第六版》电子版- Microsoft Visual C++. NET technology insider Sixth Edition, an electronic version

the c program language(2nd Edition)

约瑟夫（Joeph）问题的一种描述是：编号为1,2,…,n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数）。一开始任选一个正整数作为报数上限值m，从第一个人开始按顺时针方向自1开始顺序报数，报到m时停止报数。报m的人出列，将他的密码作为新的m值，从他在顺时针方向上的下一个人开始重新从1报数，如此下去，直至所有人全部出列为止。试设计一个程序求出出列顺序。-Joseph (Joeph) a description of the problem is: numbered 1,2, ..., n, n individuals sitting clockwise circle, each holding a password (positive integer). An optional start a positive integer as the number of reported upper limit of m, from the first person to embark on the clockwise direction starting from a reported sequence number, to report the number of m stop reported. Those who reported m out of the column, his password as the new m value, from his home in a clockwise direction on the next person started to re-reported from a few, and so on, until all of the column until all the up. Try a program designed to find out the column order.