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较好的计算阻尼Newton法的C++程序,可以很快得到较精确的结果...
较好的计算阻尼Newton法的C++程序,可以很快得到较精确的结果-Better calculation of the damping Newton method C++ program, you can quickly get more accurate results
- 2022-02-15 06:41:09下载
- 积分:1
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浙江大学程序设计大赛ACM2191题我自己收集的
浙江大学程序设计大赛ACM2191题我自己收集的-Zhejiang University Design Competition ACM2191 that my own collection
- 2022-03-17 03:11:28下载
- 积分:1
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这是一个小程序,用于二部匹配
This is a small program for bipartite matching-This is a small program for bipartite matching...
- 2022-09-18 09:35:03下载
- 积分:1
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genetic algorithm combined with neural networks, in the hope of a brighter guida...
遗传算法结合神经网络的思想,希望给你指点光明-genetic algorithm combined with neural networks, in the hope of a brighter guidance to you
- 2022-08-18 20:08:17下载
- 积分:1
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the procedures used Matlab language trend of the computer program.
该程序用matlab语言编写的计算机潮流计算程序。-the procedures used Matlab language trend of the computer program.
- 2023-07-31 20:50:02下载
- 积分:1
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基于聚类的医学图像分割法
本程序为M文件,运行环境为matlab, 也可通过matlab转化为C++运行。实现功能:可实现医学图像的自动分割!
- 2023-02-14 12:30:04下载
- 积分:1
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求解对角线元素很小的矩阵的逆矩阵,避免一般求逆的溢出问题,用Fortran编写...
求解对角线元素很小的矩阵的逆矩阵,避免一般求逆的溢出问题,用Fortran编写-small diagonal elements of the matrix inverse matrix inversion generally avoid the overflow problems, Fortran prepared
- 2022-07-13 06:23:04下载
- 积分:1
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! 平面杆系结构静力分析程序 ! 先处理法源程序 ! ! 主要功能和特点: ! 可调数组 ! 输入单元结点编号和结点位移编码; ! 先处理法形成总体刚度阵和结构...
! 平面杆系结构静力分析程序 ! 先处理法源程序 ! ! 主要功能和特点: ! 可调数组 ! 输入单元结点编号和结点位移编码; ! 先处理法形成总体刚度阵和结构综合结点荷载 ! 存储总刚上三角元素; ! GAUSS消元法解线性代数方程组; ! 计算结点位移和单元杆端力-! Plane truss structure static analysis program! First treatment source!! Main functions and characteristics:! Adjustable array! Input module node number and node displacement coding ! First approach to form and structure of the overall stiffness matrix Consolidated Statement point load! storage total just on the triangular element ! GAUSS elimination method solving linear algebraic equations ! computing node displacement and force unit rod end
- 2022-12-24 13:40:03下载
- 积分:1
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贪吃蛇算法题
应用背景某个公司的面试题,贪吃蛇,用动态规划求解最佳路径。蛇从屏幕左端走到右边,经过格子可以得分,求最大得分关键技术动态规划,DP。一列一列的递归,右边一列的值取决于左边一列的值,从左到右最后获得全局解。
- 2022-02-05 16:24:21下载
- 积分:1
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正整数x 的约数是能整除x 的正整数。正整数x 的约数个数记为div(x)。例如,1,2,5,10 都是正整数10 的约数,且div(10)=4。设a 和b 是...
正整数x 的约数是能整除x 的正整数。正整数x 的约数个数记为div(x)。例如,1,2,5,10 都是正整数10 的约数,且div(10)=4。设a 和b 是2 个正整数,a≤b,找出a 和b之间约数个数最多的数x。
对于给定的2 个正整数a≤b,编程计算a 和b 之间约数个数最多的数。
数据输入
输入数据由文件名为input.txt的文本文件提供。文件的第1 行有2 个正整数a和b。
结果输出
程序运行结束时,若找到的a 和b 之间约数个数最多的数是x,将div(x)输出到文件output.txt中。
输入文件示例 输出文件示例
input.txt output.txt
1 36 9
-Positive integer x can be about a few of the positive integer x divisible. Positive integer x the approximate number recorded as the number of div (x). For example, 1,2,5,10 are about 10 positive integer number, and div (10) = 4. Set a and b are two positive integers, a ≤ b, to find a and b between about a few number of the largest number of x. For a given two positive integers a ≤ b, Programming calculated a and b between about a few number of the largest number. Data entry input data from the document text file named input.txt provide. File line 1 has two positive integers a and b. The results run the end of the output, if found between a and b of about a few number o
- 2023-04-13 05:20:03下载
- 积分:1