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问题描述:
一杯沸水冷却,圆柱体模型,底面半径0.05m,高0.1m,周围温度20度,初始水温100度
方程是四维输运方程(常数a^2=k/(c*...
问题描述:
一杯沸水冷却,圆柱体模型,底面半径0.05m,高0.1m,周围温度20度,初始水温100度
方程是四维输运方程(常数a^2=k/(c*p),k是热传导系数0.6006焦/(米*秒*度))
初始条件:t=0时水等于100度
边界条件:1.上下壁都是自由冷却,第三类边界条件,周围温度保持在20度(H=k/h,h取1)
2.杯壁绝热,第二类边界条件
图形显示格式,取过圆柱轴的截面温度变化将其做成动画.
-Problem description : a cup of boiling water cooling cylinder model, the bottom radius of 0.05m, 0.1m high. temperature around 20 degrees, initial temperature of 100 degrees equation is four-dimensional equations (a constant ^ 2 = k/(c* p), k is the thermal conductivity coefficient of 0.6006 Coke/(m** seconds degrees)) initial conditions : t = 0 to 100 degree water boundary conditions : 1. upper and lower walls are free cooling, the third boundary conditions, maintain the temperature around 20 degrees (H = k/h, h for 1) 2. Beibi insulation, The second category boundary conditions graphics format, cylindrical shaft for the cross section of its temperature changes caused animation.
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- 积分:1
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用你的聪明才智和细心,逃出这个房间,你能吗?
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This is a preparation with the five fingers FLASH chess procedures, the procedur...
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- 2023-06-25 03:55:03下载
- 积分:1
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iso_iec_14496
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Machinery Industry Press Ya
机械工业出版社刘亚峰电子商务概论PPT课件共十章-Machinery Industry Press Ya-Feng Liu a total e-commerce courseware PPT Introduction to Chapter 10
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[Fibonacci computation Dev
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- 2023-02-07 07:45:03下载
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计算机网络第4版(谢希仁著)课后习题答案
计算机网络第4版(谢希仁著)课后习题答案
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- 2023-01-05 03:50:04下载
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USB 1.1的verilog代码,已通过FPGA验证
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