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iPhone
iphone-testsqlite是在IPHONE上使用SQLITE的测试源码, 对于在IPHONE做应用很有用.-Objective-C SQLite Wrapper is a free SQLite wrapper class that is available for both Mac OS X and iPhone.
- 2022-12-25 03:30:03下载
- 积分:1
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一个用VB编写的一维四点格式算法的源程序,很好用
一个用VB编写的一维四点格式算法的源程序,很好用-one prepared by the VB one-dimensional 4:00 algorithm source format, with a good
- 2023-04-20 12:35:04下载
- 积分:1
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平衡支架
读取的字符一一 ;
忽略任何不是支架的一些种类;
所有左括号内推入堆栈 ;
为每一个右括号,请确保位于堆栈中的类型相匹配的左的括号和弹出 ;
可能会出现三种错误:
到达最后一步输入的现在还有 (左) 括号在堆栈上 ;
你找到一个右括号中输入,但在堆栈的顶部左的一个不匹配 (即,它不是同一种) ;
您尝试匹配一个右括号与左一个从堆栈,但在堆栈为空 ;
- 2023-07-15 21:35:03下载
- 积分:1
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求最大公约数和最小公倍数的程序,输入两个数,能求出最大公约数和最小公倍数...
求最大公约数和最小公倍数的程序,输入两个数,能求出最大公约数和最小公倍数-seek common denominator and implements procedures to import two few, the common denominator can be obtained and implements
- 2022-02-11 22:12:42下载
- 积分:1
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This is a classic look for the nearest point of the algorithm, using VC preparat...
这是一个经典的寻找最近点对的算法实现,运用VC编写,采用类的方式,是程序更易理解。-This is a classic look for the nearest point of the algorithm, using VC preparation, the type used, the way the process easier to understand.
- 2022-02-05 11:01:24下载
- 积分:1
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用C++实现大容量数据的快速读入文件,以及快速写入磁盘!...
用C++实现大容量数据的快速读入文件,以及快速写入磁盘!-with C++ realization of the large-capacity, rapid data read from documents, and fast into the disk!
- 2022-07-12 23:48:52下载
- 积分:1
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数据结构 习题
数据结构 习题-data structure Exercises
- 2022-03-24 18:19:13下载
- 积分:1
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arithmetic functions example, an algorithm, the book store all the arithmetic fu...
算法函数实例,算法1,存放了书中所有的算法函数程序以及例子中的主函数程序-arithmetic functions example, an algorithm, the book store all the arithmetic functions procedures and examples of procedures for the main function
- 2023-06-18 02:05:04下载
- 积分:1
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VFP学生管理系统
VFP学生管理系统,包括注册,管理以及数据统计-VFP student management system
- 2022-04-06 09:25:46下载
- 积分:1
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Order to map any of the distance between two nodes, (2) with two
求图的任两结点间的距离,(2) 用二维数组存放C和A ,C是原成本矩阵,A 是求出的距离矩阵
(3) 算法采用三重循环,其中最外层的循环变量必须代表中间结点,中层的循环变量代表头结点而内层循环变量代表尾结点。
(4) 试着把三层循环变量的顺序作些改变,最外层的循环变量仍代表中间结点,而中层循环变量代表尾结点,内层循环变量代表头结点。把两种做法所得结果作比较,看结果是否相同
(5) 显示结果要清晰易懂
(6) 本题运行结果
-Order to map any of the distance between two nodes, (2) with two-dimensional array of storage C, A, C is the original cost matrix, A is to find the distance matrix (3) The algorithm uses the triple loop, one of the most outer loop variable must be representative of intermediate nodes, the middle loop variable represents the first node and the inner loop variable represents the end nodes. (4) tried to three-loop order of the variables to make some changes, the most outer loop variables still represent intermediate nodes, while the middle loop variable represents the end nodes, the inner loop variable represents the first node. The two approaches to compare the results to see whether the results the same (5) shows the results must be clear and understandable (6) The q
- 2022-04-20 12:55:19下载
- 积分:1