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stc12c5a60s2 单片机的ucos ii 多任务操作系统
stc12 单片机 ucosII 操作系统源码(Stc12 MCU ucosII operating system source code)
- 2017-12-16 12:22:05下载
- 积分：1
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另类HotButton
本源码是基于Visual C++的，是一种Hot按钮，这种按钮有它独特的一面(this source is based on Visual C, and it is a Hot button, the button has its unique side)
- 2005-06-24 22:37:13下载
- 积分：1
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7041831USBDriver
仅用于tp900掌机的usb驱动。安装简单方便。-Only the usb driver for tp900 handheld. Easy to install.(Writing From the information carefully detailed features, including the content description (at least 20 words). Try not to let owners to spend time on your revised instructions. When extracting archive can not have a password.)
- 2011-06-11 10:55:33下载
- 积分：1
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algorithms(CPP)
计算机常用数值算法与程序(C++版) (Commonly used numerical algorithm of computer and program
)
- 2014-01-04 22:46:59下载
- 积分：1
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STC8_Delay
次代码是针对STC8系列的单片机的延时函数，使用
此代码可以直接添加调用，程序自动获取内部系统时
钟后初始化延时函数。只要是ISP软件默认的时钟频
率都可以应用（特殊频率除外）
该代码为初版，还存在很多缺陷，请各位大佬勿喷，谢谢！
注意：
次代码仅适用于STC公司最新的STC8系列单片机(Delay Function of Single Chip Microcomputer)
- 2019-03-14 19:14:08下载
- 积分：1
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Metric-to-Imperial-Units-
公英制互转换器，初学VC时的小程序，对平时工程制图有些用处。(Metric to Imperial Units )
- 2013-08-28 07:13:38下载
- 积分：1
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FX1N PLC sorce code
说明： Open source plc STM32F103RBT6
STM32F103RBT6 do PLC IPC board STM32 development board simulation software source code Mitsubishi PLCFX1N
FX1N-16MR PLC program
Using ARM STM32F103 RBT6 industrial-grade chips. The latest compatible with Mitsubishi PLC programming software GX-8.86 version
Direct download software GX-8.86 version, online monitoring, program comparison, the program reads.
diy own PLC control panel, to achieve the original performance
Shorten your development time Dashboard SCM process,
Also includes online monitoring program, very easy to debug.
Open source PLC to provide you with a complete PLC program, comprising PLC schematics
8 input / 8-point output.
Mitsubishi protocol support for download, online monitoring, connect the touch screen control
- 2019-03-15 21:29:47下载
- 积分：1
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OLED程序
说明： oled显示模块显示所需的内容, 以达到人们的需求，满足人们的需要(use oled to display many content)
- 2020-06-21 09:20:01下载
- 积分：1
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Question1
说明： C++源代码，递归实现。原问题描述：鼓上蚤时迁到一个山洞里去盗宝，里面有n件宝贝，价值分别是a1,a2......an，并且满足ai大于a1+a2+....+a(i-1)的和。他身上有一个背包，能装的东西最大价值是K，他只能进洞一次，请问他最多能带出多少？
要求：输入K，n，a1，a2......an
输出：他能最多带出的宝物价值
(C++ Source code Recursive achieve. The original problem description: drum when flea盗宝going to move in a cave, there are n pieces of treasure, valued are a1, a2 ...... an, and to meet ai than a1+ A22B !....+ a (i-1) and. Him to have a backpack, things can hold the greatest value is K, he could only hole once, to ask him to bring out the maximum number of? Requirements: Enter K, n, a1, a2 ...... an output: he can bring out the maximum value of the treasures)
- 2008-12-02 21:07:25下载
- 积分：1
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CommunicationEngineerNetWorkPractise
通信工程师电信网络专业习题集 通信工程师电信网络专业习题集 通信工程师电信网络专业习题集(CommunicationEngineerNetWorkPractise CommunicationEngineerNetWorkPractise CommunicationEngineerNetWorkPractise)
- 2014-01-12 15:39:38下载
- 积分：1
