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消去法求解线性方程组。
MFC做的可视化界面。
消去法求解线性方程组。
MFC做的可视化界面。-Elimination method for solving linear equations. MFC to do visual interface.
- 2022-01-22 14:27:56下载
- 积分：1
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Not is to provide C/C++ programmer job interview guide, which aims to examinatio...
并不在于提供C/C++程序员求职面试指导，而旨在从技术上分析面试题的内涵。文中的大多数面试题来自各大论坛，部分试题解答也参考了网友的意见。
许多面试题看似简单，却需要深厚的基本功才能给出完美的解答。企业要求面试者写一个最简单的strcpy函数都可看出面试者在技术上究竟达到了怎样的程度，我们能真正写好一个strcpy函数吗？我们都觉得自己能，可是我们写出的strcpy很可能只能拿到10分中的2分。读者可从本文看到strcpy函数从2分到10分解答的例子，看看自己属于什么样的层次。此外，还有一些面试题考查面试者敏捷的思维能力。
分析这些面试题，本身包含很强的趣味性；而作为一名研发人员，通过对这些面试题的深入剖析则可进一步增强自身的内功。
-Not is to provide C/C++ programmer job interview guide, which aims to examination questions from a technical analysis of face connotations. Most of the text surface examination questions from the major forums, part of the answer in reference to the Questions User s views.
Many face examination questions seem simple, yet profound basic skills needed in order to give the perfect answer. Company asked interviewers to write a simple strcpy function of the interview can be seen in the technology of how to achieve the extent of what we can really written a strcpy function do? We all feel that you can, but we write the strcpy is likely to receive only 10 points in 2
- 2022-03-01 08:24:29下载
- 积分：1
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这个例子是由两个独立的项目/应用程序的功能。eir_a
This example consists of two separate projects/applications eir_a for the role A device and eir_b for the role B device and uses the Connection library.
* eir_a searches for devices and then displays the information on the devices found.
* eir_b makes the device visible and responds to Bluetooth 2.1 Extended Inquiry Response (EIR) requests.
This ReadMe is not intended to describe procedures that are covered in the xIDE user guide such as building projects in xIDE etc.
-This example consists of two separate projects/applications eir_a for the role A device and eir_b for the role B device and uses the Connection library.
* eir_a searches for devices and then displays the information on the devices found.
* eir_b makes the device visible and responds to Bluetooth 2.1 Extended Inquiry Response (EIR) requests.
This ReadMe is not intended to describe procedures that are covered in the xIDE user guide such as building projects in xIDE etc.
- 2022-05-23 05:50:40下载
- 积分：1
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机票需求分析，需求分析从一开始到包的一个G。
机票需求分析，从开始的需求分析到封装一气呵成，教你编程的基础-Ticket needs analysis, needs analysis from the beginning to the package at one go, and teach you the basis for programming
- 2022-06-02 09:09:25下载
- 积分：1
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vb做的仓库管理系统
vb做的仓库管理系统 -the warehouse management system
- 2022-02-16 01:12:42下载
- 积分：1
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This a subprogram based on the platform of win2000, recommend!
这是一个在WIN2000操作平台下的子程序，各位喜欢电脑的朋友不妨看一看，我的电脑试了哦，很好的，-This a subprogram based on the platform of win2000, recommend!
- 2022-01-26 15:03:10下载
- 积分：1
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wince platform OpenGL es under the application of an original code, lighting eff...
wince 平台下的 的一个 OpenGL es 应用的原代码，灯光效果, 用EVC4.0下编译-wince platform OpenGL es under the application of an original code, lighting effects, compiled with EVC4.0
- 2022-02-13 12:13:39下载
- 积分：1
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一个公享软件注册框的控件，使大家在做软件保护的时候更方便。...
一个公享软件注册框的控件，使大家在做软件保护的时候更方便。-Software to enjoy a public register of the control box, so that we can do when software protection and more convenient.
- 2022-04-25 10:15:06下载
- 积分：1
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基于JAVA的flappy bird游戏
较为简单的JAVA小游戏，适合初学者模仿学习，设置鼠标点击事件为小鸟向上飞，操作简单，实现比较符合新入门的朋友们，欢迎大家来看看
- 2022-10-25 18:00:03下载
- 积分：1
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Using a text file (txt) record information. Information includes: name, birthday...
采用一个文本文件(txt)记录信息。信息包括：姓名、生日、电话、Email、地址、邮编等资料，可以对记录的人员进行分组，如：亲友、同事、同学等。界面由Dos界面命令行的方式实现，功能模拟文曲星或手机的地址本,可以增加、删除、修改个人资料，可以分组人员、可以安各种信息进行模糊查询，-Using a text file (txt) record information. Information includes: name, birthday, telephone, Email, address, postcode and other information, personnel records can be grouped, such as: friends, colleagues, students and so on. Interface from the Dos command line interface means to achieve the functional simulation Wen Quxing or the phone" s address book, you can add, delete, modify personal information, you can group people, all kinds of information can be an ambiguous query,
- 2022-03-16 10:13:14下载
- 积分：1
