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求根MUSIC空间谱估计算法
传统空间谱估计算法当中,求根Root-MUSIC算法不仅计算量小,而且估计性能优越,尤其是在低信噪比时,相比MUSIC的性能又不小的提升。
- 2022-10-16 10:45:03下载
- 积分:1
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- 2022-09-25 14:35:03下载
- 积分:1
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主要是讲如何使用Vc++来制作界面,以及与数据库连接和网络编程...
主要是讲如何使用Vc++来制作界面,以及与数据库连接和网络编程-Mainly stress how to use Vc++ To create interfaces, and database connectivity and network programming
- 2022-04-25 11:54:47下载
- 积分:1
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一个ada的编译器
一个ada的编译器-a compiler
- 2023-01-09 17:15:04下载
- 积分:1
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将笛卡尔坐标系上的点定义为一个服务类Point,Point类提供求得坐标系上两点间距离的功能、获取和设置坐标的功能、获取极坐标的功能,和完成对已创建的Point...
将笛卡尔坐标系上的点定义为一个服务类Point,Point类提供求得坐标系上两点间距离的功能、获取和设置坐标的功能、获取极坐标的功能,和完成对已创建的Point类对象统计功能。设计测试Point服务类的应用程序主类,测试并显示输出提供功能的结果。(求以点(1,1)为极坐标原点,点(5,5)的极坐标)-Will be a point on the Cartesian coordinate system is defined as a service class Point, Point class provides coordinates obtained on the function of the distance between two points, access and set coordinates, polar coordinates to obtain functions, and the completion of the Point that have been created class object statistical functions. Design Test Point service class application" s main class to provide functionality to test and display the output results. (Seeking to point (1,1) to polar coordinates origin point (5,5) in polar coordinates)
- 2022-04-18 05:26:57下载
- 积分:1
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vb编写的引入系统监视器,一个非常小但实用。
vb编写的引入系统监视器,一个非常小但实用。-vb prepared by the introduction of system monitors, a small but very practical.
- 2023-07-02 23:40:03下载
- 积分:1
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BIG5 to GB2312 with characters that corresponds to data conversion. For RUBY lib...
于GB2312中与BIG5相对应繁体字编码转换。
为RUBY程式库。
-BIG5 to GB2312 with characters that corresponds to data conversion. For RUBY library.
- 2022-02-21 04:36:02下载
- 积分:1
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非常方便的滤波器设计软件,能方便的设计出多种滤波器。
非常方便的滤波器设计软件,能方便的设计出多种滤波器。-Very convenient for filter design software, to facilitate the design of a variety of filters.
- 2023-02-05 19:40:03下载
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基于灰色GM(1,1)理论的电力系统负荷预测程序
基于灰色GM(1,1)理论的电力系统负荷预测程序
-Based on Gray GM (1,1) theory of power system load forecasting procedures
- 2022-07-13 01:12:44下载
- 积分:1
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快速排序的递归解演示,用20个字符串代表20个数,显示每次分组结果,延时10000。如果在你的机子上太快,可以加长延时。...
快速排序的递归解演示,用20个字符串代表20个数,显示每次分组结果,延时10000。如果在你的机子上太快,可以加长延时。-rapid sequencing of recursive solution demonstrations, with 20 representatives of 20 string number, the results show that each packet, Delay 10000. If your machine on too fast, it could be Long Time Delay.
- 2022-02-03 23:19:22下载
- 积分:1