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可以算加减乘除24,可以求所有的解,但又重复的,没有刻意去掉...
可以算加减乘除24,可以求所有的解,但又重复的,没有刻意去掉-can calculate the arithmetic of 24, can help all the solutions, but to repeat, not deliberately removed
- 2022-05-18 01:43:43下载
- 积分:1
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makes a snowflake in opengl and glut functions
makes a snowflake in opengl and glut functions
- 2022-07-09 09:24:15下载
- 积分:1
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终端 IEC104源代码,ucos平台
终端 IEC104源代码,ucos平台
终端 IEC104源代码,ucos平台
终端 IEC104源代码,ucos平台
- 2022-07-18 18:56:32下载
- 积分:1
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递归枚举模板
问题描述:生成长度为n的字串,其字符从26个英文字母的前p(p≤26)个字母中选取,使得没有相邻的子序列相等。例如p=3,n=5时:
//...
递归枚举模板
问题描述:生成长度为n的字串,其字符从26个英文字母的前p(p≤26)个字母中选取,使得没有相邻的子序列相等。例如p=3,n=5时:
// abcba 满足条件
// abcbc 不满足条件
//输入:n p
//输出:所有满足条件的字串及总数-recursive template Problem description : n generation length of the string and its 26 characters from the English alphabet before p (p 26) 000 1984 letter, makes no adjacent sequences equivalent. For example, p = 3, n = 5 :// abcba meet the conditions// abcbc not satisfied conditions// input : n p// output : to satisfy all the conditions and the total number of strings
- 2023-04-22 22:30:03下载
- 积分:1
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OpenCV的人脸检测
Face Detection from OpenCV
- 2022-07-06 11:54:09下载
- 积分:1
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曲线离散化算法,douglas_peucker算法。
曲线离散化算法实现,Douglas_Peucker算法。-Curve discretization algorithm, Douglas_Peucker algorithm.
- 2023-04-14 05:05:04下载
- 积分:1
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solve a matrix problems. Look at specific problems documented. And the source.
解决一个矩阵问题。具体的问题看文件说明。和源码。-solve a matrix problems. Look at specific problems documented. And the source.
- 2023-03-27 09:10:03下载
- 积分:1
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read books from archive
#包括;
- 2023-02-20 16:55:04下载
- 积分:1
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c语言的更深一步编程,有一定的开发基础的学习用
c语言的更深一步编程,有一定的开发基础的学习用-Some advanced C program, for veterans
- 2022-05-19 00:41:13下载
- 积分:1
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实现标准库函数strstr的功能:在str1中查找str2,若找到,返回指向str1中第一次出现str2的位置;
int A ( const char...
实现标准库函数strstr的功能:在str1中查找str2,若找到,返回指向str1中第一次出现str2的位置;
int A ( const char * str1, const char * str2 );
没有的话,返回-1 有则返回所在位置(从0开始)
写出函数,对编写函数main完成对strstr的功能的验证。
-achieve the standard library functions strstr function : the search for str2 str1, if found, str1 return at the first appearance of str2 position; Int A (const char* str1, const char* str2); If not, the return-1 is returned with the location (from starting at 0) write function, the main function prepared to complete the function of the strstr certification.
- 2022-07-22 04:47:08下载
- 积分:1