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anti_f_aloha
此代码为RFID中防冲突算法中的固定帧ALOHA算法的仿真(this code for RFID defense algorithm conflict fixed frame ALOHA Simulation Algorithm)
- 2021-04-11 18:08:58下载
- 积分：1
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射频识别技术是自动识别技术…
无线射频识别技术(RFID)是自动识别技术的一种高级形式。随着信息化技术的不断发展，无线射频识别技术(RFID)的应用也越来越广泛。本书主要介绍了无线射频识别技术的基本工作原理和具体应用，并列举了大量的应用实例，如动物识别管理、配送中心管理、矿井管理、停车场管理、军事物流运用等-Radio frequency identification technology (RFID) is the automatic identification of an advanced form of technology. As information technology continues to develop, radio frequency identification technology (RFID) applications are increasingly widespread. This book introduces the radio frequency identification technology, the basic working principles and specific applications, and listed a large number of application examples, such as animal identification management, distribution center management, mine management, car park management, the use of military logistics
- 2022-09-24 22:25:03下载
- 积分：1
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RFID_anti_collision_algorithm
电子标签防碰撞是RFID 系统中一个关键问题。在射频识别系统中．当阅读器作用范围内有多个标签同时向阅读器发送数据时，会产生冲突，必须采用一种防碰撞算法解决这种冲突。在分析典型的二进制及动态二进制防碰撞算法基础上，采用了一种新的防碰撞算法。经实验证明，该算法能有效解决射频识别系统中多目标识别的防碰撞问题。(Tag anti-collision RFID system is a key issue. In the radio frequency identification systems. When the reader within the framework of the role of multiple tags simultaneously send data to the reader, it will create conflict, you must use a anti-collision algorithm to solve such conflicts. In the analysis of a typical binary and dynamic anti-collision algorithm based on the binary, using a new anti-collision algorithm. The experiments show that the algorithm can effectively solve the radio frequency identification system, multi-target recognition of the anti-collision problem.)
- 2021-04-11 17:58:57下载
- 积分：1
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51单片机RFID汽车门禁系统
基于AT89C52单片机 12864液晶显示 继电器作为开关
- 2023-07-26 14:10:03下载
- 积分：1
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chirp-fourier-transform
chirp fourier transform 线性调频Z变换(CZT) 的matlab功能函数，该方法通过CZT变换获得精确的等价于离散傅里叶变换结果的间谐波信号的频率分布估计值,可以得到精确的各次谐波和间谐波参数,利用该函数相同采样频率下该方法的检测精度更高。(This routine allows the evaluation of the DFT over an arbitrary range of frequencies as its name implies this lets you zoom into a narrow portion of the spectrum.)
- 2013-10-22 23:08:06下载
- 积分：1
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RFID
rfid simulink仿真程序，rfid流程(rfid simulink simulation program, rfid process)
- 2011-10-11 05:35:12下载
- 积分：1
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RG.PhotoelectricGateControl
说明： RFID读写器，可对RFID标签进行读写，实时获取RFID信息(RFID reader can read and write RFID tags and obtain RFID information in real)
- 2020-08-18 15:21:54下载
- 积分：1
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模拟S50卡片
单片机控制PN532，模拟S50卡片，支持id号改写（特殊卡号除外），支持扇区读写，整机即为一张卡片，可通过普通mifare读卡器操作
- 2023-05-30 07:10:03下载
- 积分：1
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无线射频识别（RFID）正在迅速改变商业交易…
射频确认((RFID)正迅速改变生意跟踪盘货和资产的方式.从对美国国防部沃尔-马特和特斯科,早期努力正已经展示好处,但是为RFID软件,融合和数据处理使目前一挑战平息下来.如果你是一个设计师把发展一RFID系统记在一开发者金色上的,这本书是给你的.广阔经验鼓励,比尔Glover和Himanshu Bhatt为你提供重要的关于这新兴技术的信息.
-Radio Frequency Identification (RFID) is rapidly changing the way businesses track inventory and assets. From Wal-Mart and Tesco to the US Department of Defense, early efforts are already showing benefits, but software, integration, and data processing for RFID still present a challenge. If you are a developer or an architect charged with developing an RFID system, this book is for you. Drawing on extensive experience, Bill Glover and Himanshu Bhatt provide you with essential information on this emerging technology.
- 2022-01-22 17:23:50下载
- 积分：1
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matlab
一种无限定位，toa时延定位算法的代码。matlab源程序 希望采纳( |
| SCRIPT: simMLE
|
| PURPOSE: Simulate a relative location system by generating
| random measurements and maximizing the likelihood fcn.
| After many trials, show the results vs. the Cramer-Rao Bound.
|
| AUTHOR: Neal Patwari
| http://www.engin.umich.edu/~npatwari/
|
| REFERENCE: Relative Location Estimation in Wireless Sensor Networks
| (N. Patwari, A. O. Hero, M. Perkins, N. S. Correal, R. J. O Dea),
| IEEE Trans. Signal Processing, vol. 51, no. 8, Aug. 2003, pp. 2137-2148.
|
tic
Use globals to allow minimization functions access to network info,
debugging info.
global refDevices blindDevices totalDevices linearRefLocs dhat funcEvals dfuncEvals
Basic simulation parameters
roomSize = [1,1] Room size, meters
gridSize = 5 How many sensors per side
refDevices = 4 How many references (must be same length as actualRefLocs)
trials = 20 How many inde)
- 2012-04-29 13:54:34下载
- 积分：1
