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这个是vb编写的控制服务器的程序，还包括一个于此相关的视频教程...
这个是vb编写的控制服务器的程序，还包括一个于此相关的视频教程-This is the control server vb preparation procedures, this also includes a related video tutorial
- 2022-07-17 15:13:16下载
- 积分：1
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environment : windows98/2000/xp, Visula 6.0 C compiler through. The current mode...
环境:windows98/2000/xp,Visula C++6.0下编译通过.模型采用的目前非常流行的C/S架构,TCP/IP通信协议-environment : windows98/2000/xp, Visula 6.0 C compiler through. The current model is very popular C/S architecture, TCP/IP communication protocol
- 2023-02-21 00:05:04下载
- 积分：1
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asp.net 仓库仓储管理系统源代码
asp.net 仓库仓储管理系统源代码-asp.net warehouse warehouse management system source code. . . .
- 2022-01-25 20:12:30下载
- 积分：1
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基于matlab和C，包括LMS,CMA,MCMA自适应均衡器的程序和论文，论文说明很详细，可以提供相关参考...
基于matlab和C，包括LMS,CMA,MCMA自适应均衡器的程序和论文，论文说明很详细，可以提供相关参考-Including the LMS, CMA, MCMA adaptive equalizer procedures and papers, research papers explain in great detail and can provide relevant information
- 2023-04-13 16:25:03下载
- 积分：1
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非常强大的打印控件，我们一直用他，价格便宜量又足
非常强大的打印控件，我们一直用他，价格便宜量又足-Very powerful print controls, we have been with him, the volume also cheap enough
- 2022-01-26 03:04:24下载
- 积分：1
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多功能计算器
void
mainmenu() /*主菜单*/
void
Integermenu /*整数运算的菜单*/
void
realnumbermenu() /* 请点击左侧文件开始预览 ！预览只提供20%的代码片段，完整代码需下载后查看 加载中 侵权举报
- 2022-06-12 13:04:39下载
- 积分：1
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简单的活动目录和LDAP的应用
simple active directory and LDAP utils
- 2023-07-27 07:15:03下载
- 积分：1
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解决以下问题：
For solving the following problem:
"There is No Free Lunch"
Time Limit: 1 Second Memory Limit: 32768 KB
One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free.
However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.
- 2022-12-06 21:00:03下载
- 积分：1
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This is a C Programming Document
这是一个C++编程文档-This is a C Programming Document
- 2022-01-26 06:57:18下载
- 积分：1
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ε-贪婪的行动选择
epsilon greedy action selec
- 2022-01-27 21:20:19下载
- 积分：1
