-
In this paper, on the one hand, to produce the form of examples of the types of...
本文一方面以实例的形式介绍产生数据封锁的各类情况,另一方面从数据库理论的角度加以分析,以期使读者既知其然,更知其所以然,使读者能够更加深入地理解Oracle的数据封锁机制,而不是简单地记住某些结论。-In this paper, on the one hand, to produce the form of examples of the types of data on the situation of the blockade, on the other hand, the theoretical point of view from the database to be analyzed in order to make the reader not only know-and know所以然, so that readers can be more in-depth understanding of Oracle data blockade mechanism, rather than simply to remember some of the conclusions.
- 2022-06-02 15:41:14下载
- 积分:1
-
先验扫描
什么都不
- 2022-07-26 22:51:28下载
- 积分:1
-
数据结构底层经典算法――时间陷阱,请大家参考
数据结构底层经典算法――时间陷阱,请大家参考-underlying data structure classical algorithm-- time trap, please refer to
- 2022-06-18 17:32:41下载
- 积分:1
-
数据结构C++语言描述
数据结构C++语言描述--应用标准模板库-Data Structures C++ language description- Application of Standard Template Library
- 2022-01-21 06:04:06下载
- 积分:1
-
C语言学习,由一个多项式抓准备,主要的检查方法…
学习C语言时,编写的一个多项式刮号检查程序
主要用栈实现的。-C language study, prepared by a polynomial scratching, the main inspection procedures Stack realized.
- 2022-03-24 20:03:55下载
- 积分:1
-
哈夫曼树的建立源代码。。。
共享给各位啦
哈夫曼树的建立源代码。。。
共享给各位啦-Huffman tree to establish the source code. . . Sharing to Members啦
- 2022-02-25 21:03:56下载
- 积分:1
-
项目描述: SQLite is a small C library that implements a self
项目描述: SQLite is a small C library that implements a self-contained, embeddable, zero-configuration SQL database engine. Features include- Project description: SQLite is a small C library that
implements a self-contained, embeddable, zero-configuration SQL
database engine. Features include
- 2022-01-22 13:40:01下载
- 积分:1
-
list容器源代码
应用背景
它实现的是一个可存储各种类型数据的链表,可用于数据的交换、存储、分析前的存储和排序。
关键技术使用C++ 类的特性编写的一个类似标准STL的容器“链表”,可以实现对任何类型的数据操作,使用了迭代器、类模板等,来简化链表的使用,有泛型编程的一些东西。
- 2022-02-04 14:18:06下载
- 积分:1
-
Visual basic + sql server2000学员管理系统原代码
Visual basic + sql server2000学员管理系统原代码-Visual basic+ sql server2000 student management system source
- 2022-12-26 17:50:08下载
- 积分:1
-
求解约瑟夫问题。设有n个人围成一个圆圈坐下,对所有围从的人从某个位置开始编号为1,2,3,……,n,从编号为1的人开始报数1,报数依交进行,报数n的人即出列,下...
求解约瑟夫问题。设有n个人围成一个圆圈坐下,对所有围从的人从某个位置开始编号为1,2,3,……,n,从编号为1的人开始报数1,报数依交进行,报数n的人即出列,下一个人从1开始报数,再报数m的人便是第二个出列的人如此重复下去,直到最后一个人出列为止,于是便得到一个出列的顺序,这称之为约瑟夫(Josephu)问题。-solving problems. N individuals have formed a circle to sit down, all right Wai from the start from a position of No. 1, 2, 3, ..., n, for a number of people reported a few, according to several newspaper pay, the newspaper n ie the out, the next person was from the beginning a few , and reported m is the second out of this series continue to repeat until the final out in a series, then get a series out of order, which called Joseph (Josephu) problem.
- 2022-05-21 23:13:13下载
- 积分:1