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asdaasdasda
ASDAASDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDAASDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDdddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
- 2022-03-20 19:42:52下载
- 积分:1
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最件单的求值问题..就是求井深和绳长的问题,,我还是个初学者...
最件单的求值问题..就是求井深和绳长的问题,,我还是个初学者-most pieces of the single-issue .. evaluates depth and is seeking a long rope, and I was a beginner, and laughter
- 2022-07-19 00:03:09下载
- 积分:1
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libsvm训练
资源描述LIBSVM是台湾大学林智仁(Lin Chih-Jen)教授等2001年开发设计的一个简单, 易于使用和快速有效的SVM模式识别与回归的软件包,
他不但提供了编译好的可在Windows系列系统的执行文件, 还提供了源代码, 方便改进, 修改以及在其它操作系统上应用;
该软件对SVM所涉及的参数调节相对比较少, 提供了很多的默认参数, 利用这些默认参数可以解决很多问题; 并提供了交互检验(Cross
Validation)的功能. 该软件包可在http://www.csie.ntu.edu.tw/~cjlin/ 免费获得.
该软件可以解决C-SVM, ν-SVM, ε-SVR和ν-SVR等问题, 包括基于一对一算法的多类模式识别问题.
- 2023-06-05 13:25:03下载
- 积分:1
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labview 奥运五环
资源描述这是用labview写的一个显示奥运五环的程序 喜欢的就拿去吧
- 2022-01-25 22:21:18下载
- 积分:1
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LABVIEW中的SPWM
这是在 labview 的 spwm 3 阶段。
学生只有一个示例去想怎么能做一种三相逆变器使用 labview 和 DAQ。
- 2022-03-03 13:44:15下载
- 积分:1
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自适应小波分析
作为小波变换的推广,线性调频小波变换在对信号进行时频表示时具有更多的自由度,是对非平稳信号进行时频分析的有力工具,在视频平面上,常见的小波变换是零阶逼近,而线性调频小波是一阶逼近。
- 2023-05-07 02:45:02下载
- 积分:1
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编排万年日历,学习多个函数的编写及调用,提高综合测算能力。...
编排万年日历,学习多个函数的编写及调用,提高综合测算能力。-scheduling calendar years, learning various functions and the preparation of call, to increase the overall capacity calculations.
- 2022-01-26 02:34:00下载
- 积分:1
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实现一个超过了计算机所表示范围的长整数的加减法
实现一个超过了计算机所表示范围的长整数的加减法-achieve an over by the computer, said the scope of the long integer addition and subtraction
- 2023-04-11 17:05:03下载
- 积分:1
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n皇后问题的进阶解法,算法简单,注意输入的N可能没有解,比如2...
n皇后问题的进阶解法,算法简单,注意输入的N可能没有解,比如2-n Queen of the intermediate solution, the algorithm is simple, pay attention to the N input may not solved, such as the two
- 2022-07-08 20:45:07下载
- 积分:1
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素数环: 把从1到10这10个数摆成一个环,要求相邻的两个数的和是一个素数。 〖问题分析〗 这是一道回溯的题目。从1开始,每个空位有9种可能,每种可能加入约束...
素数环: 把从1到10这10个数摆成一个环,要求相邻的两个数的和是一个素数。 〖问题分析〗 这是一道回溯的题目。从1开始,每个空位有9种可能,每种可能加入约束条件即可
1.与前面所有的数不重复
2.与前一个数和为素数(最后一个和第一个也要满足)。 〖算法流程〗 1、数据初始化; 2、递归填数: 判断第J种可能是否合法; A、如果合法:填数;判断是否到达目标(10个已填完): 是,打印结果;不是,递归填下一个; B、如果不合法:选择下一种可能;-Prime Central: 1-10 from 10 the number of put this into a ring, asked the two adjacent numbers and is a prime number. 〗 〖Analysis is a retrospective this topic. From 1 year, 9 out of every space possible, each may be bound by the conditions of accession to 1. And in front of all the number of non-repetition, 2. With a few and for a prime number (the last and the first to meet). 1〗 〖algorithm processes the data to initialize 2, fill in the number of recursion: first to determine the legality of J possible A, if the legitimate: the number of Reclamation to determine whether the target (10 have been completed): Yes, print the results of not, fill in the next recursive B, if not legitimate: a possible alternative
- 2022-03-13 12:39:07下载
- 积分:1