登录
首页 » 加密解密 » 对于C和C++几乎Rijndael的整数运算。

对于C和C++几乎Rijndael的整数运算。

于 2022-08-20 发布 文件大小:5.31 MB
0 80
下载积分: 2 下载次数: 1

代码说明:

Arithmetic for integers of almost rijndael for C and C++. Developed for linux-Arithmetic for integers of almost rijndae l for C and C. Developed for linux

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • Compare Two Files HMACSHA1 VB 2005
    Compare Two Files HMACSHA1 VB 2005
    2022-03-13 01:07:44下载
    积分:1
  • iTunes的饼干
    应用背景 ;在泰瑞MAA KI十字脉辛格关键技术jhoom巴拉酒吧 ;jhoom巴拉酒吧
    2022-04-24 19:19:51下载
    积分:1
  • s-Demo2.0 加密解密算法-s-Demo2.0
    2022-07-24 21:32:07下载
    积分:1
  • RSA
    RSA-1.02VERSION
    2023-09-05 10:05:03下载
    积分:1
  • 笔者长期从事移动通信系统的无线链路调制与调、物理层实现方面的工作。在移动通信GSM系统中,我们进行语音或者业务信道调时,都会遇到CRC的求。通常在硬件DS...
    笔者长期从事移动通信系统的无线链路调制与解调、物理层实现方面的工作。在移动通信GSM系统中,我们进行语音或者业务信道解调时,都会遇到CRC的求解。通常在硬件DSP实现时,特别是40位CRC求解时候,由于生成多项式有41项,DSP最大一次能处理40位,所以使用单个寄存器会遇到一些困难,那么以下这个程序将会解决这一困难(这是针对定点DSP、C55xx的编程实现方法)。-The author has long been engaged in mobile communication system modulation and demodulation of wireless links, the physical layer to achieve work. GSM in the mobile communications system, we have a voice or channel demodulation operations, it will encounter the solution of CRC. DSP hardware usually realize, especially when solving the 40 CRC, as the generation polynomial has 41, DSP can handle the largest 40, so using a single register may encounter some difficulties, then following this process will solve this One difficulty (which is for fixed-point DSP, C55xx realize programming methods).
    2022-06-18 05:18:56下载
    积分:1
  • 微机接口规范有关定时器。
    Microprocesser interfacing codes relating to timers.
    2022-06-17 21:00:05下载
    积分:1
  • IPSEC源码包括测试模块代码,容易移植
    资源描述在IP层加密的IPSEC源码,包括各个模块的测试代码,可以针对具体的TCPIP协议栈进行移植,本人已经在uc/tcpip协议栈上进行了移植,测试成功,实现了局域网内多个节点的安全通信
    2023-03-10 15:45:03下载
    积分:1
  • SUPER LOSHINAYA PROGA!!!!!!!!11
    SUPER LOSHINAYA PROGA-SUPER LOSHINAYA PROGA!!!!!!!!11
    2022-05-20 19:21:38下载
    积分:1
  • 应用程序向导创建了这个cngcryptfile应用
    The application wizard has created this CNGCryptFile application for you. This application not only demonstrates the basics of using the Microsoft Foundation Classes but is also a starting point for writing your application.
    2022-03-22 01:12:10下载
    积分:1
  • Xor called symmetric encryption module's function can be
    Xor对称加密 调用模块里的函数即可-Xor called symmetric encryption module"s function can be
    2023-07-08 00:05:03下载
    积分:1
  • 696518资源总数
  • 104269会员总数
  • 31今日下载