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旅行商问题
某售货员要到若干城市去推销商品，已知各城市之间的路程（或旅费）。他要选定一条从驻地出发，经过每个城市一遍，最后回到驻地的路线，使总的路程（或旅...
旅行商问题
某售货员要到若干城市去推销商品，已知各城市之间的路程（或旅费）。他要选定一条从驻地出发，经过每个城市一遍，最后回到驻地的路线，使总的路程（或旅费）最小。
例如：给定4个城市{1，2，3，4}及其各城市之间的路程
最优路线是1,3,2,4,1，
其最短路程是25-a salesman, traveling salesman problem, a number of cities to sell commodities, the known distance between the city (or travel). He selected from a resident, after each city again, the last resident to return to the line, making the total distance (or travel) is the smallest. For example : given four cities (1,2,3,4) and the distance between the city optimal route is 1,3,2,4, 1, the shortest distance is 25
- 2022-03-31 13:34:20下载
- 积分：1
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拉格朗日插值函数算法的示例
拉格朗日插值函数算法的示例-Lagrangian function interpolation algorithm examples
- 2022-07-21 17:26:50下载
- 积分：1
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SimpleAlgorithm
- 2022-07-16 22:31:36下载
- 积分：1
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A Reader Anti-collision Protocol for RFID-Enhanced Wireless Sensor Networks
资源描述Abstract Considering rapid developments in the technologies of both radio-frequency identification
(RFID) systems and wireless sensor networks (WSN), an integration of the two
technologies may lead to the formation of an RFID-enhanced WSN which would possess
improved functions and capabilities. In the RFID-enhanced WSN, many reader-enhanced
nodes have increasingly been employed. In such networks, RFID data contains a lot of duplication,
because the same tag may be read multiple times, and collision may occur among
readers, while energy constraints are also a serious problem. These three could in turn cause
serious problems. In this paper, we have proposed our CSMA-based algorithm since it is light,
efficiently minimizes all kinds of reader collision, and eliminates the duplicate data. For this
purpose, we have used a separate control channel and a tag ID forwarding mechanism with a
special co
- 2023-05-06 18:20:03下载
- 积分：1
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nec moment program by fortran
nec moment program by fortran
- 2022-10-23 07:50:04下载
- 积分：1
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EFG2D-hole，带孔圆板问题的EFG程序，matlab
程序为采用matlab写的一个带孔圆板的EFG程序，这是一个学习和验证算法的标准算例，给出了可调控网格密度的网格生成程序，做数值算法的必学的程序
- 2023-04-20 22:05:03下载
- 积分：1
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计算个人所得税的代码5522197 5522197 5522197
计算个人所得税的代码5522197 5522197 5522197-the calculation of personal income tax code 5522197 5522197 5522197 5522197
- 2022-04-08 19:28:14下载
- 积分：1
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一个最短路径算法，可以作为初学参考，具有一定的价值和扩展空间...
一个最短路径算法，可以作为初学参考，具有一定的价值和扩展空间-A shortest path algorithm, can serve as a beginner reference, has a certain value and the expansion of space
- 2022-07-12 00:51:37下载
- 积分：1
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ADOV 的 Tcl 脚本
TCL 脚本对 AODV ；请下载并享受。这是写在 NS2 帮助别人得到的 NS2 的窍门。任何帮助请联系 ashwin.kannan1@gmail.com
- 2022-05-08 20:16:04下载
- 积分：1
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毕业设计四轴飞行
这是匿名论坛小陀毕业设计的源代码。程序参考了匿名和圆点博士的不凡驱动和核心算法！非常棒的参考资料！
- 2022-02-13 03:55:44下载
- 积分：1
