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依次输入数字(大于0)，当输入max求最大值
简介
利用do while做循环判断
截图
代码
- 2021-09-25 00:30:55下载
- 积分：1
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Printing
Printing from any printer
- 2012-08-04 03:59:02下载
- 积分：1
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immediately-communication
即时通信，实现两个人之间短距离的通信。
可实现长时间的通信。(immediately communication)
- 2013-01-27 00:56:52下载
- 积分：1
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AIC23
基于TI DSP c672x的音频信号处理,音频编解码芯片采用AIC23，通过I2C对AIC23进行操作。(Based on TI DSP c672x audio signal processing, audio codec chip AIC23, AIC23 carried on through the I2C operation.)
- 2013-09-16 23:18:28下载
- 积分：1
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缠论MT4精准画笔指标
自动画缠论笔，经反复测试，画线非常精准，不知道有木有大神能把他改成EA(Auto-wrapping argumentation pen, after repeated testing, drawing line is very accurate, do not know that there is a wood God can change him into EA)
- 2018-11-16 20:40:27下载
- 积分：1
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medo
设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组，每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。 编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n（n<=200），表示每个数组有n个数。接下来的两行分别是X，Y数组的元素。结果输出 程序运行结束时，将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits. programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)
- 2021-03-22 16:29:16下载
- 积分：1
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可以演示代码，演示源代码，可供模块
CAN demo code,demo source code for CAN module -demo source code for CAN module
- 2022-02-12 04:16:36下载
- 积分：1
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BPANN
基于BP神经网络的字符识别算法源代码，包括网络仅值训练方法，训练是通
过调用34个字符文件夹，识别率达到99.8 。(BP neural network-based character recognition algorithm source code, including the value of the network only training methods, training is by calling the 34-character file folders, the recognition rate of 99.8 .)
- 2015-01-10 22:59:33下载
- 积分：1
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NewGestureSensorV1.0
STM32平台下使用LTC2400来采样数值，采取SPI的进行通讯。(By using the STM32 platform，use LTC2400 to sample values, use the SPI communication.)
- 2020-11-30 20:59:27下载
- 积分：1
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GPS
GPS定位数据解析，GPS设备通过对接收到的导航电文进行分析处理，计算出设备所在的经纬度、海拔、航速、航向等空间信息，并按照规定的NMEA-0183协议将空间信息以及卫星信息进行组织，按照一定的波特率通过串口通讯（按位发送）提供给GPS设备使用者或者在GPS设备上进行显示(GPS positioning data analysis, GPS device by the received navigation message analysis and processing equipment where the calculated latitude and longitude, altitude, speed, heading and other spatial information and spatial information and satellite information is organized in accordance with the provisions of the NMEA-0183 protocol , according to the baud rate of serial communication (bits sent) to the users of GPS devices or GPS devices on display)
- 2012-06-25 21:42:13下载
- 积分：1
