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C series of the small program, a very good thing.
用C++编的小程序,很好的。-C series of the small program, a very good thing.
- 2022-04-22 09:03:11下载
- 积分:1
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一个演示通过Hook监控鼠标键盘的例子.
一个演示通过Hook监控鼠标键盘的例子.-a demonstration by Hook monitor mouse and keyboard example.
- 2022-08-24 18:34:41下载
- 积分:1
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递归的应用:最简单分形图形实现ksqx
递归的应用:最简单分形图形实现ksqx-recursive applications : the most simple Fractal Graphics ksqx
- 2022-04-12 06:50:13下载
- 积分:1
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本程序用于输出文件到桌面(桌面路径从注册表自动读取)
本程序用于输出文件到桌面(桌面路径从注册表自动读取)-This procedure for the output file to the desktop (desktop path automatically read from the registry)
- 2022-07-08 06:27:28下载
- 积分:1
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计算机编程和维护所有的源代码包含D。
电脑编程技巧与维护全部Delphi源代码,包含几十个使用的源代码。-computer programming skills and maintenance of all Delphi source code contains dozens of source code.
- 2022-10-14 23:40:03下载
- 积分:1
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本系统的名称为“小型图书馆管理系统”,它具有以下功能: 1.借书,还书 2.增书,删书 3.按作者名或专业领域检索图书 4.查找被某为读者借走的一批书 5.查找
本系统的名称为“小型图书馆管理系统”,它具有以下功能: 1.借书,还书 2.增书,删书 3.按作者名或专业领域检索图书 4.查找被某为读者借走的一批书 5.查找最近借走某书的读者 6.查找某管理员的操作记录. 备注:① 管理员分四类:借书管理员,还书管理员,采编管理员(增书,删书),馆长助理 ② 读者有最大借书量 ③ 图书未归还前,不能对它进行借书操作.-the system known as "mini-library management systems," it has the following functions : 1. Library, book 2. Zeng, adding three books. According to the author or professional search field 4. A search was to take readers through a number of book five. You go through a recent book readers 6. the search for a caretaker operational records. Note : administrators at four categories : library administrators, book manager, editorial manager (by, censored books), the Assistant Curator readers have the greatest volume library books had not returned before it can operate for the library.
- 2023-08-23 11:35:04下载
- 积分:1
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EEP
基于eEP的两阶段方法分类,自己还没看完,有需要的人可以看看,不知道咋样 -EEP-based two-stage method of classification, not their reading, those in need can see, I do not know咋样
- 2022-01-20 23:19:08下载
- 积分:1
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又一个Ping的例子
又一个Ping的例子-another example of a Ping
- 2022-08-07 07:05:00下载
- 积分:1
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算符优先分析程序 实验时做的一个小程序
算符优先分析程序 实验时做的一个小程序-Operator priority analysis program to do the experiment a small program
- 2022-05-08 07:03:11下载
- 积分:1
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有n个整数,使其前面各数顺序向后移m个位置,最后m个数变成最前面的m个数...
有n个整数,使其前面各数顺序向后移m个位置,最后m个数变成最前面的m个数-There are integers n, the number of its previous order of the backward shift position m, and finally the number m of m into the top of the number of
- 2022-03-25 22:59:30下载
- 积分:1