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这是英国Kent大学开发的进程代数的JAVA库,对付多线程和并发系统变得很容易,有大量的范例,我们导师很看好的东西...
这是英国Kent大学开发的进程代数的JAVA库,对付多线程和并发系统变得很容易,有大量的范例,我们导师很看好的东西-developed at the University of Kent in the process algebra JAVA basement, deal with multithreading and concurrency system is very easy, we have a lot of examples, we have very good instructors things
- 2022-03-10 04:49:06下载
- 积分：1
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常见插值方法及其介绍
“Inverse Distance to a Power（反距离加权插值法）”
“Kriging（克里金插值法）”
“Mi...
常见插值方法及其介绍
“Inverse Distance to a Power（反距离加权插值法）”
“Kriging（克里金插值法）”
“Minimum Curvature（最小曲率)”
“Modified Shepard s Method（改进谢别德法）”
-common interpolation methods and introduced "Inverse Distance to a Power (Anti- distance weighted interpolation) "" Kriging (Kriging) "," Minimum Curvat ure (the smallest curvature) "" Modified Shepard"s Method (improving Xie other Germany and France ) "
- 2022-12-03 23:45:03下载
- 积分：1
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一个程序来模拟光通过一个玻璃球。
One program to simulation light passing through a glass sphere.
It is interesting and can be used in geometric optics.
- 2022-01-21 02:06:10下载
- 积分：1
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yufafenxi
余发芬西
- 2022-02-05 22:00:00下载
- 积分：1
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利用状态表和有限自动机的运行原理编制程序，使得程序能够识别一个输入串是否为一个有效的符号串...
利用状态表和有限自动机的运行原理编制程序，使得程序能够识别一个输入串是否为一个有效的符号串-tables and the use of the limited state of the automatic machine operation principle procedures, making procedures to identify whether an input string as a symbol effective Series
- 2022-08-11 14:09:13下载
- 积分：1
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8051的ipcore。本人调试过 ，非常好用
8051的ipcore。本人调试过 ，非常好用-8051 人 linked cavity ipcore 。 ， Toru Tan试are suspect using quasi-
- 2022-10-11 03:35:03下载
- 积分：1
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解决以下问题：
For solving the following problem:
"There is No Free Lunch"
Time Limit: 1 Second Memory Limit: 32768 KB
One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free.
However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.
- 2022-12-06 21:00:03下载
- 积分：1
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该文件包含RS码编译码的相关资料和两个版本的C源码，对进行RS编码和译码的同仁希望有帮助...
该文件包含RS码编译码的相关资料和两个版本的C源码，对进行RS编码和译码的同仁希望有帮助
- 2022-02-11 20:39:44下载
- 积分：1
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memory management, mitigation, use vc6 compile.
内存管理, 减少碎片, 使用vc6编译通过.-memory management, mitigation, use vc6 compile.
- 2022-03-02 04:39:25下载
- 积分：1
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89c51单片机内部所有寄存器功能介绍（89X5X.H），并有详细的中文资料...
89c51单片机内部所有寄存器功能介绍（89X5X.H），并有详细的中文资料-89c51 microcontroller all the registers within the functional description (89X5X.H), and detailed information in Chinese
- 2023-06-29 08:55:04下载
- 积分：1
