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4用户指南Lonworks NodeBuilder Gizmo
LonWorks NodeBuilder Gizmo 4 Users Guide
- 2022-03-11 21:01:43下载
- 积分：1
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一个汽车的fuzzy的控制,能很好地应用FUZZY的特点
一个汽车的fuzzy的控制,能很好地应用FUZZY的特点-a car fuzzy control can be well applied to the characteristics FUZZY
- 2022-12-30 03:05:04下载
- 积分：1
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arbitrary download
任意下载——构建自己的Linux网络蚂蚁，希望对Linux/UNIX的学习者能有一定的启发
- 2022-07-25 17:16:29下载
- 积分：1
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shangjiao6.m为主程序；pcode.m为产生伪码的子程序；bu.m为进行补0的子程序（为了使得进行FFT和IFFT的点数满足2的N次方个） c_b.m...
shangjiao6.m为主程序；pcode.m为产生伪码的子程序；bu.m为进行补0的子程序（为了使得进行FFT和IFFT的点数满足2的N次方个） c_b.m为数据进行串并转换的子程序。-shangjiao6.m-based procedures pcode.m for producing pseudo-code subroutine bu.m for fill 0 Subroutine (carried out in order to make the point FFT and IFFT of the N-th power to meet the 2 months) c_b.m for data for string and conversion subroutine.
- 2022-05-20 09:20:20下载
- 积分：1
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Face Detection system, developed using opencv face detection process
人脸检测系统，利用opencv开发的人脸检测程序-Face Detection system, developed using opencv face detection process
- 2022-01-21 22:39:52下载
- 积分：1
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索尼社区的地方2和mulit_users VRML浏览器。
sony community place broswer 2.0 for VRML and Mulit_Users.
- 2022-03-07 03:14:15下载
- 积分：1
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陈列馆问题：
1.问题描述
世界名画陈列馆有m*n个陈列室组成。为了防止名画被盗，需要在陈列室设置警卫机器人哨位，每算法个警卫机器人除了监视它所在的陈列...
陈列馆问题：
1.问题描述
世界名画陈列馆有m*n个陈列室组成。为了防止名画被盗，需要在陈列室设置警卫机器人哨位，每算法个警卫机器人除了监视它所在的陈列室之外，还可以监视与它所在的陈列室相邻的上，下，左，右4个陈列室。
2.要求
试要求，设计一个安排警卫机器人哨位的算法，使得名画陈列馆的每个陈列室都在警卫机器人监视之下，切所用的警卫机器人数目最少。
3.结果输出
将计算的警卫机器人数及其最佳哨位安排输出到文件output.txt。文件的第1行是警卫机器人数；接下来的m行中每行n个数，0表示无哨位，1表示哨位。-Gallery problem:
1. Problem Description
Painting gallery in the world there are m* n composed of a showroom. In order to prevent the paintings stolen, you need to set the security robot sentinel showroom, each algorithm is a security robot in addition to monitor it in the showroom, you can also watch it in the showroom with the adjacent upper and lower, left, Right 4 showrooms.
2. Demand
Test requirements, design an arrangement guard robot sentinel algorithm, making paintings in each gallery showroom are under the surveillance of the security robot, cutting the number of robots used by security guards at least.
3. The resulting output
Will calculate the number of security robots and the best sentinel ar
- 2022-06-27 18:30:39下载
- 积分：1
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Broadband Series
Broadband Series - ATM Basics 2-Broadband Series- ATM Basics 2
- 2022-02-26 02:39:25下载
- 积分：1
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串口调试软件，支持自动发送，支持多串口，不是源码，转发
串口调试软件，支持自动发送，支持多串口，不是源码，转发-Serial debugging software to support the automatic transmission, support multi-serial port, not source code, forwarding
- 2022-04-25 09:27:57下载
- 积分：1
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是程序计算从选定的点的地形图的可见性。我..
这个程序可以计算给定点处的小区信号范围覆盖。-is program computes a map of visibility from a selected point on a topography. It has been written to help the search for radio relay best location. Because it considers only direct line of sight, it gives a good estimation for possible radio link for short distances only (less than 10 km), neglecting curvature of the Earth, Fresnel zone and atmospheric refraction on radio waves propagation. The program computes the relative elevation angle of the mask for each point (the angle is null or negative if the point is visible).
The function needs a digital elevation model Z and associated (X,Y) vectors or matrices of coordinates (same unit as Z), position of the point (X0,Y0), the antenna height H0 (for instance 4 m), and the hypothetic antenna height Ha on each topography points (for instance 3 m). When no output argument is given, the function plots a map of the results (color map of mask angles, and blank for visible points, see example screenshot).
The s
- 2022-06-27 17:42:17下载
- 积分：1
