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演示解析传输流文件
Demo parsing TS transport stream files
- 2022-03-04 19:13:11下载
- 积分:1
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VisualC++应用技巧与常见问题你问我答
为初学者提供,希望对大家有帮助!
分三部分传...
VisualC++应用技巧与常见问题你问我答
为初学者提供,希望对大家有帮助!
分三部分传-VisualC++ Application techniques and frequently asked questions you ask me to provide A for beginners, and they hope to have everyone help! Communication is divided into three parts
- 2022-05-10 21:50:14下载
- 积分:1
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很精致的冲浪计数器
很精致的冲浪计数器-very delicate counter surfing
- 2022-01-21 02:07:58下载
- 积分:1
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基于OFDM-OQAM系统的信道估计
这是关于ofdm-oqam系统的基本框架仿真,里面不仅包含滤波器的设计,还有PAPR抑制,是学习OFDM-OQAM系统的初学者不错的选择。
- 2022-06-13 03:49:10下载
- 积分:1
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手写板识别
资源描述联机数字、英文字符及汉字识别,mydate.dat为字库先点击file, 点open,读入字库
学习时字库自动保存
已有键盘字符,字母,数字
和简单汉字
如要识别复杂汉字,请先用学习功能
- 2022-02-05 13:37:34下载
- 积分:1
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This is WINCC study on some of the information, I hope to give a rookie like me...
这是关于WINCC学习的一些资料,希望能给象我这样的菜鸟一些帮助-This is WINCC study on some of the information, I hope to give a rookie like me some help
- 2023-02-15 20:35:04下载
- 积分:1
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An animated simulation of a vertical pinball bouncing movements, each attenuatio...
模拟一个动画弹球的垂直弹跳的动作,每次衰减为上次高度的0.9,考虑重力加速度。-An animated simulation of a vertical pinball bouncing movements, each attenuation for the last time a high degree of 0.9, consider the acceleration of gravity.
- 2022-11-05 11:00:04下载
- 积分:1
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一个小工具,可用于文件中文字内容的替换,支持多递归搜索文件...
一个小工具,可用于文件中文字内容的替换,支持多递归搜索文件-a small tool can be used to document text replacement, support multiple recursive search files
- 2022-11-30 14:15:03下载
- 积分:1
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日历的源代码
这是日历的 c + + 的源代码。附有验收程序,欢迎下载,试用。谢谢您的支持。
- 2022-05-29 09:00:37下载
- 积分:1
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八皇后VC图形演示,算法思想:回溯法,先在第1行放上一个皇后,然后在第2行合适的位置放上一个皇后,依次类推,如果8行都放满了,说明找到了一个解,如果第好第i行的...
八皇后VC图形演示,算法思想:回溯法,先在第1行放上一个皇后,然后在第2行合适的位置放上一个皇后,依次类推,如果8行都放满了,说明找到了一个解,如果第好第i行的皇后后,第i+1行找不到合适的位置,这时就回到第i行,把第i行的皇后放到下一个位置,继续尝试下一行。如此反复,知道找到所有的解。注意,这种算法找的解可能有等价的,某些解可由别的解经过旋转棋盘得到。-visual demostration in vc of eight queens problem.
algorithm: backtracking.
First, put a queen on first line then find a suitable position on 2nd line for next queen, and so on. When all eight lines have queens, it means we have find a solution. If we put the i-th queen, but can find a suitable position on the (i+1)th line, then back to the ith line and move the queen on the ith line to next suitable position and move on to the next line. Repeat this until we have found all the solutions. Note:By this mean, some solutions maybe equivalent to others, some can be acquired by the rotation of other solutions.
- 2022-03-23 15:20:19下载
- 积分:1