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DOS下的通用四串口测试程序,用于测试串口是否能正常工作。
DOS下的通用四串口测试程序,用于测试串口是否能正常工作。-DOS generic four serial test procedure for testing whether the serial port to work properly.
- 2022-05-28 08:52:00下载
- 积分:1
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计算函数f(x1,x2)=100*(x1^2
计算函数f(x1,x2)=100*(x1^2-x2)+(1-x1)^2
的全局最大值-Calculation of function f (x1, x2) = 100* (x1 ^ 2-x2)+ (1-x1) ^ 2 of the overall maximum
- 2022-01-26 15:27:17下载
- 积分:1
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用C语言实现的卡尔曼滤波+小波分析结合的数字信号处理方法,所有子函数与主函数包含在两个文件中...
用C语言实现的卡尔曼滤波+小波分析结合的数字信号处理方法,所有子函数与主函数包含在两个文件中-With the C language implementation of the Kalman filter+ wavelet analysis combined with digital signal processing method, all the main function subroutine contained in the two documents
- 2022-07-21 18:25:23下载
- 积分:1
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对于,在Win CE平台采用开源ffmpeg的手臂亲实现…
针对H264,在win CE平台 利用开源的FFMPEG对ARM处理器优化实现的版本-For H264, in the win CE platform using open source FFmpeg realize on the ARM processor optimized version
- 2022-01-26 04:02:03下载
- 积分:1
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C++时钟模拟时钟,准备模拟时钟的分钟操作…
C++ 时钟模拟 可以准备模拟时钟的时针分针秒针的运行-C++ clock analog clock, ready to simulate the operation of the clock the minute hand second hand
- 2022-04-08 03:16:52下载
- 积分:1
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ecshop仿三九妈咪母婴网2015最新版
ecshop仿三九妈咪母婴网2015最新版非常不错的一套商城开源源码。现在拿出来和大家分享一下,个人开源,个人用途禁止商业开发。
- 2022-10-09 06:55:07下载
- 积分:1
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内存驻留程序的基本思想就是让程序一直停留在内存中,不断的执行特定的命令。但内存驻留如何被执行呢?一般地,内存驻留程序都是通过修改BIOS或DOS的系统中断向量表...
内存驻留程序的基本思想就是让程序一直停留在内存中,不断的执行特定的命令。但内存驻留如何被执行呢?一般地,内存驻留程序都是通过修改BIOS或DOS的系统中断向量表来实现的。比如修改向量表中16H位置的中断(这个中断接收键盘的按键,在DOS中,按键按下,这个中断就会被调用),让其指向我的程序,这时若有按键被按下,则执行的是我的程序。-The basic idea is to let procedure has to remain in the memory and keeps the implementation of specific orders. But the presence of memory how to be executed? Generally, the memory presence procedures are revised BIOS or DOS systems to scale interruption to achieve. For example, changes to the set-16H location of the interrupt (the keyboard interrupt reception of keys, DOS, press the button, the suspension will be called), let me point to the procedure, if time was pressing the button, I was the implementation of the procedures.
- 2022-03-07 21:10:22下载
- 积分:1
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This program demonstrates a magic trick.
这个程序演示了一个魔术。
- 2022-03-19 23:57:32下载
- 积分:1
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很好的一个Maze算法
很好的一个Maze算法-a good Maze Algorithms
- 2022-01-25 20:05:53下载
- 积分:1
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A组
用汇编语言实现:在屏幕上显示:
SIN(X)+345*X/67
X=?
REXUILT=
等待输入一个任意的十进制数X(假设每个数不...
A组
用汇编语言实现:在屏幕上显示:
SIN(X)+345*X/67
X=?
REXUILT=
等待输入一个任意的十进制数X(假设每个数不超过三位),计算上述表达式的结果,将该结果显示出来:对于XIN(X)的计算结果要求采用子程序编写,主程序用于输入X和显示结果。
B组:
汇编程序写一个能与PC当前运行的程序进行分时操作的程序,程序的功能是演奏“五星红旗迎风飘扬”。并设置有热键,可随时终止或恢复演奏。
C组:
用汇编程序编程编写一个动画程序:有一架飞机在显示屏幕的上方,从左至右,忽高忽地,周而复始的飞行,屏幕下方设有一门高射炮,该炮可人工控制左右移动,人工控制空格键发射炮弹,炮弹命中飞机后,声光大作。(要求使用图形显示方式)
-A group
Using assembly language to achieve: on the screen:
SIN (X)+345* X/67
X =?
REXUILT =
Waiting for input an arbitrary decimal number X (the assumption that the number of not more than three each), calculated the results of the above expression, the results are displayed: For XIN (X) requires the calculation of the results of the preparation subroutine, main program for Enter the X and the result will be displayed.
B:
Assembler to write a PC currently running with the process time-sharing operating procedures, procedures for the function is to play "five-star red flag fluttering in the wind." And set up hotkeys, may terminate
- 2022-04-25 18:27:40下载
- 积分:1