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Introduced into the interactive thread, can also be written, there is a need to...

于 2022-04-28 发布文件大小:36.85 kB

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介绍了线程交互编成，写的还可以，有需要的同僚可以看看.-Introduced into the interactive thread, can also be written, there is a need to look at colleagues.

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2023-07-12 04:00:03下载

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no more-no more,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

2023-07-11 16:45:03下载

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[1] 考勤时间=2005
[1] 考勤时间=2005-10-27 员工编号=1 状态=迟到上班时间(早)=16:59:40 备注=无 [2] 考勤时间=2005-10-27 员工编号=2 状态=迟到上班时间(早)=16:59:40 备注=无 [3] 考勤时间=2005-10-27 员工编号=3 状态=迟到上班时间(早)=16:59:40 备注=无 [6] 考勤时间=2005-10-27 员工编号=6 状态=早退上班时间(早)=上午 18:52:45 备注=无下班时间(晚)=上午 18:52:45 [5] 考勤时间=2005-10-27 员工编号=5 状态=早退上班时间(早)=上午 19:01:40 备注=无下班时间(晚)=上午 19:01:40 [4] 考勤时间=2005-10-27 员工编号=4 状态=早退上班时间(早)=上午 19:04:14 备注=无下班时间(晚)=上午 19:04:14 -[1] time = 2005-10-27 employees attendance number = 1 state = late working hours (early) = 16:59:40 Note = No [2] time = 2005-10-27 employees attendance number = 2 status = late working hours (early) = 16:59:40 Note = No [3] time = 2005-10-27 employees attendance number = 3 state = late working hours (early) = 16:59:40 Note = No [6] Attendance time = 2005-10-27 employee ID = 6 state = leave early to go to work hours (early) = 18:52:45 AM Remarks = no working hours (late) = 18:52:45 AM [5] attendance period = 2005-10-

2022-08-15 07:26:19下载

积分：1
LCS问题就是求两个字符串最长公共子串的问题。解法就是用一个矩阵来记录两个字符串中所有位置的两个字符之间的匹配情况，若是匹配则为1，否则为0。然后求出对角线最长...
LCS问题就是求两个字符串最长公共子串的问题。解法就是用一个矩阵来记录两个字符串中所有位置的两个字符之间的匹配情况，若是匹配则为1，否则为0。然后求出对角线最长的1序列，其对应的位置就是最长匹配子串的位置。最长递增子序列LCS的实现C源码！-LCS problem for two strings is the longest common sub-string problem. Solution is to use a matrix to record the location of two strings of all the matches between the two characters in the situation, if the match is one, otherwise to 0. And one of the longest diagonal obtained sequence, the location of its corresponding sub-string match is the longest position. The longest increasing sub-sequence source C implementation of the LCS!

2022-08-19 18:20:36下载

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Introduced into the interactive thread, can also be written, there is a need to...

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