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限定程序的使用时限
限定程序的使用时限--Configure the use time limit for programs.
- 2022-01-26 04:46:53下载
- 积分：1
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一个简单的碟片出租管理系统，使用VB和ACCESS编写。
一个简单的碟片出租管理系统，使用VB和ACCESS编写。-a simple disc rental management system, using VB and Access prepared.
- 2022-03-18 17:23:00下载
- 积分：1
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RTP 通信开源项目源码
rtp通信开源项目源码，适合任何平台，目前已经基本成熟。按照RFC3550实现,这使得它很容易地发送和接收RTP包和RTCP（RTP控制协议）.
- 2022-02-10 14:52:46下载
- 积分：1
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/ *我已经编译两次，第二次的改进。改进思路…
/*本人先后编了两次，第二次进行了改进。改进的思想主要是注意到棋盘上每一点的下一可到达点的个数
（下称为权值）不同，对于可到达点较少（权值小）的点应该先跳上去，这样后来跳的点可跳的方向就比
较多，回溯的现象就比较少，这样就可以大幅度提高速度*/-/* I have compiled twice, the second time for improvements. Improved thinking is that every point on the chessboard of the next point can be reached by the number (hereinafter referred to as the right value), For less accessible spots (small weights) should be the first point and jumped out of the way and then jump to the point of jumping on the direction of more, Looking back on the phenomenon of relatively small, we can significantly improve the speed* /
- 2022-03-20 16:40:03下载
- 积分：1
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这是一个不错的ASP的翻页程序,和大家一起分享。
这是一个不错的ASP的翻页程序,和大家一起分享。-This is a good page of the ASP program, and the U.S. share.
- 2023-01-04 07:05:03下载
- 积分：1
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实现MFC不规则对话框，一个漂亮的时钟计时器实例，
实现MFC不规则对话框，一个漂亮的时钟计时器实例，-The realization of irregular MFC dialog box, and a beautiful example of the clock timer,
- 2023-01-04 21:20:03下载
- 积分：1
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C++做到飞行游戏，比较好玩，可以供参阅和学习
C++做到飞行游戏，比较好玩，可以供参阅和学习-C++ to do the flight game, more fun, can be used for reference and learning. .
- 2022-06-27 20:24:05下载
- 积分：1
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一个用VC实现对XML编译的源码。在VC6中开发。MSXML为4.0版，在微软网上可以下到，是免费的。有问题联系nomygod163@163.com...
一个用VC实现对XML编译的源码。在VC6中开发。MSXML为4.0版，在微软网上可以下到，是免费的。有问题联系nomygod163@163.com-VC with a pair of XML compiler source code. In VC6 developed. MSXML version 4.0 of the Microsoft Internet can make to be free. Problems associated nomygod163@163.com
- 2023-05-11 03:35:03下载
- 积分：1
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解决以下问题：
For solving the following problem:
"There is No Free Lunch"
Time Limit: 1 Second Memory Limit: 32768 KB
One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free.
However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.
- 2022-12-06 21:00:03下载
- 积分：1
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最近点对问题，输入数据生成器自动生成2位点对，输出制定电的最近邻...
最近点对问题，输入数据生成器自动生成2位点对，输出制定电的最近邻-nearest point of the problem, the input data generator automatically generate two points right, electrical output of the nearest neighbor
- 2022-12-16 08:40:03下载
- 积分：1
