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显示WINDOWS所有窗体的示例代码程序，可决定将窗口显示或隐藏...
显示WINDOWS所有窗体的示例代码程序，可决定将窗口显示或隐藏-show all forms of sample code, may decide to window to show or hide
- 2022-07-09 14:16:06下载
- 积分：1
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Maze procedure, with the stack, the realization of two
迷宫程序，用堆栈，实现二维数组，迷宫是一个固定的行，也可以从文件中读取
- 2022-07-10 00:45:25下载
- 积分：1
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a small software in compile theory,let s enjoy your s .
编译原理的中的一点小软件,看看大家的软件.-a small software in compile theory,let s enjoy your s .
- 2022-02-24 12:59:37下载
- 积分：1
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一个可以运行DOS程序（正确的说法应该是Windows下的控制台程序）并且捕捉程序输出的源程序...
一个可以运行DOS程序（正确的说法应该是Windows下的控制台程序）并且捕捉程序输出的源程序-one can run DOS (The correct statement should be Windows console procedures) and procedures for capturing output of the source
- 2022-06-28 01:21:41下载
- 积分：1
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一个基于C++编写的程序，功能是形象的描绘水和火
一个基于C++编写的程序，功能是形象的描绘水和火-Based on the C++ Preparation procedure, function is to portray the image of water and fire
- 2022-08-04 08:54:27下载
- 积分：1
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这是我课程设计时做的一个小游戏，编得不太好，请各位高手指教！...
这是我课程设计时做的一个小游戏，编得不太好，请各位高手指教！-This is my courses designed to do a little game, the series it very well, experts advise you!
- 2022-06-02 05:08:51下载
- 积分：1
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许可选项文件和可替换为用户一
License Options file and may replace Named Users for a
Program, whether temporarily or not, no more than four (4)
times per year, prov
file never exceeds the number licensed per Program.
Portions of the Programs may be installed on individual
computers to accelerate startup times, as long as the-License Options file and may replace Named Users for a Program. whether temporarily or not. no more than four (4) times per year. 577 file never exceeds the number licensed per Program. Portions of the Programs may be instal led on individual computers to accelerate star tup times, as long as the
- 2022-01-26 03:59:17下载
- 积分：1
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Measured slant range of the operator to the Gauss projection plane side length o...
将实测斜距化算至高斯投影平面边长的边长改正程序-Measured slant range of the operator to the Gauss projection plane side length of the side length correction procedure
- 2023-05-04 13:45:03下载
- 积分：1
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本程序针对约瑟夫问题的描述：编号为12，……n的n个人按顺时针方向围成一圈，每人持有一个密码（正整数），一开始任选一个正整数作为报数上限值m，从第一个人开始按顺...
本程序针对约瑟夫问题的描述：编号为12，……n的n个人按顺时针方向围成一圈，每人持有一个密码（正整数），一开始任选一个正整数作为报数上限值m，从第一个人开始按顺序时针方向自1开始顺序报数，报道m时停止报数，报m的人处列将他的密码作为新的m值，从他在顺时针方向上的下一个人开始重新从1报数，如此下去，直至所有人全部出列为止。利用单向循环链表存储结构模拟此过程，按照出列的顺序印出各人的编号。
演示程序以用户和计算机的对话方式执行，即在计算机终端上显示“提示信息”下，用户输入循环人数n和每人的密码。-This procedure description specifically for Joseph problem: The serial number is 12, ... The n n individual surrounds the ready-made one circle according to the clockwise sense , each person holds (positive integer) a password, one positive integer beginning to assume a post of selections is upper limits ms numbering off, direction starts the hour hand beginning from the first people according to order from 1 numbering off in proper order , stop numbering off when reporting m, the person place column reporting m looks on his password as new m value , the individual begins to number off again from 1 , getting down like this from his time as soon as going ahead in clockwise sense, until proprietor all till leaving self s place in the ranks.
- 2022-10-13 13:15:03下载
- 积分：1
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此程序是用排序实现换位递规的的版本， 对程序的操作有一定的帮助作用...
此程序是用排序实现换位递规的的版本， 对程序的操作有一定的帮助作用-This program realizes the conversion recursion by sorting, making some use to operation of program.
- 2022-03-29 10:12:21下载
- 积分：1
