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this document for LCD driver chips for Samsung KS0093 spent mainly on the COG
此文件为液晶驱动芯片 为三星的KS0093 主要用在COG上-this document for LCD driver chips for Samsung KS0093 spent mainly on the COG
- 2022-03-25 18:12:28下载
- 积分：1
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box frame _ _ combination of rolling bo x frame _ _ combination of rolling List...
列表框_组合框_滚动条
列表框_组合框_滚动条
-box frame _ _ combination of rolling bo x frame _ _ combination of rolling List Box _ _ rolling box combination of the list box frame _ _ combination of rolling box _ _ rolling portfolio of the box
- 2022-08-23 21:32:01下载
- 积分：1
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wince下用evc4.0开发的俄罗斯方块游戏，使用于新x86平台。
wince下用evc4.0开发的俄罗斯方块游戏，使用于新x86平台。-wince under development with evc4.0 Tetris game, for use in the new x86 platform.
- 2022-03-19 07:39:03下载
- 积分：1
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显示屏测试程序的源程序
显示屏测试程序的源程序-display the source code of the test procedure
- 2023-05-22 14:15:03下载
- 积分：1
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MATLAB Programming Guide,
MATLAB程序设计教程》源代码-2660 MATLAB程序设计教程》源代码-2660 MATLAB程序设计教程》源代码-2660-MATLAB Programming Guide,
- 2023-06-19 22:45:04下载
- 积分：1
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c编程技巧１００之５
c编程技巧１００之５-hundred five
- 2022-07-15 04:41:50下载
- 积分：1
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type names age categories to show animals
通过类型姓名年龄类别来显示动物-type names age categories to show animals
- 2022-05-18 12:31:05下载
- 积分：1
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Monte
用蒙特卡洛法实现对排队等待问题的计算机模拟
-Monte-Carlo method to realize the problem of computer simulation of waiting
- 2023-07-04 07:50:03下载
- 积分：1
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Z值渲染，VB＋M0开发的GIS源代码，可以在二维图上增加Z值，实现第三维操作...
Z值渲染，VB＋M0开发的GIS源代码，可以在二维图上增加Z值，实现第三维操作-Z value rendering, VB M0 developed GIS source code, can be increased in two-dimensional map of Z values, the realization of the third-dimensional operation
- 2022-05-01 01:53:33下载
- 积分：1
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解决以下问题：
For solving the following problem:
"There is No Free Lunch"
Time Limit: 1 Second Memory Limit: 32768 KB
One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free.
However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.
- 2022-12-06 21:00:03下载
- 积分：1
