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一次作业的源码,功能可能太简单,仅供参考
一次作业的源码,功能可能太简单,仅供参考-One-stop source, function might be too easy, for reference only
- 2022-07-19 01:43:39下载
- 积分：1
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电驴开放源代码
emule open source code -EMule open source code
- 2023-04-03 21:10:04下载
- 积分：1
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进程查询列表， 主要是WINDOWS中经常出现的进程名，然后进程解释说明。...
进程查询列表， 主要是WINDOWS中经常出现的进程名，然后进程解释说明。-The process of query list is WINDOWS that often appear in the process name, and then the process of explanation.
- 2022-01-25 20:45:13下载
- 积分：1
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一个探测窗口信息的类Spy++小工具
一个探测窗口信息的类Spy++小工具-a window to detect the type of information Spy small tools
- 2022-09-17 08:10:03下载
- 积分：1
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VC源码
VC源码-VC source R11/0350V0400N
- 2022-08-14 08:19:22下载
- 积分：1
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ppp protocol source code associated with the Siemens MC35 Singlechip
ppp协议源代码
与西门子MC35单片机相连-ppp protocol source code associated with the Siemens MC35 Singlechip
- 2022-10-14 13:25:08下载
- 积分：1
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曾经有位网友和我讨论怎样编写一个通过服务器对客户机上的程序进行自我升级的问题，由于我的项目也涉及到自我升级，当时我把我的解决方案提了出来，那就是做一个类似于瑞星...
曾经有位网友和我讨论怎样编写一个通过服务器对客户机上的程序进行自我升级的问题，由于我的项目也涉及到自我升级，当时我把我的解决方案提了出来，那就是做一个类似于瑞星的升级程序。在这里我也发现了很多的网友对这个问题很困惑，故我愿意把我的设计方案写出来与大家共享，大家也可以通过这个思路用其他语言进行改写-had one netizen and I discussed how to prepare a server through the client on the procedures for self-promotion , I am also involved in the project to self-promotion, I use my solution mentioned, it is so similar to the one Ruixing promotion procedures. Here I also found a lot of online friends to the problem is very confused, Therefore, I am willing to put my design write and share. Members can also thinking through the use of other languages rewritten
- 2023-04-21 21:40:02下载
- 积分：1
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窗口的安全代码
Writing Secure Code for Windows Vista
- 2022-04-24 09:56:31下载
- 积分：1
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LCS问题就是求两个字符串最长公共子串的问题。解法就是用一个矩阵来记录两个字符串中所有位置的两个字符之间的匹配情况，若是匹配则为1，否则为0。然后求出对角线最长...
LCS问题就是求两个字符串最长公共子串的问题。解法就是用一个矩阵来记录两个字符串中所有位置的两个字符之间的匹配情况，若是匹配则为1，否则为0。然后求出对角线最长的1序列，其对应的位置就是最长匹配子串的位置。 最长递增子序列LCS的实现C源码！-LCS problem for two strings is the longest common sub-string problem. Solution is to use a matrix to record the location of two strings of all the matches between the two characters in the situation, if the match is one, otherwise to 0. And one of the longest diagonal obtained sequence, the location of its corresponding sub-string match is the longest position. The longest increasing sub-sequence source C implementation of the LCS!
- 2022-08-19 18:20:36下载
- 积分：1
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shellex source code download
shellex源代码下载
- 2022-12-13 10:50:04下载
- 积分：1
