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系统工程中的平滑预测法，根据一些数据预测为了某一个时期的数值...
系统工程中的平滑预测法，根据一些数据预测为了某一个时期的数值-project of the Ievel, according to some data in order to forecast a period of numerical
- 2022-10-25 00:05:03下载
- 积分：1
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ansj分词停词代码
使用中文分词包ansj进行分词停词的代码使用中文分词包ansj进行分词停词的代码使用中文分词包ansj进行分词停词的代码使用中文分词包ansj进行分词停词的代码使用中文分词包ansj进行分词停词的代码使用中文分词包ansj进行分词停词的代码
- 2022-07-13 00:30:03下载
- 积分：1
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VB_PC-DMIS
在v40 PC-DMIS脚本函数用于定制DMIS出口(后)
请点击左侧文件开始预览 ！预览只提供20%的代码片段，完整代码需下载后查看 加载中 侵权举报
- 2023-05-30 19:10:03下载
- 积分：1
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冒泡排序
冒泡排序-bubble sort
- 2022-02-01 03:11:51下载
- 积分：1
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为实现fdtd3d平面波TF / TS编码
code for implementation FDTD3D with plane wave tf/ts
- 2022-05-06 05:44:54下载
- 积分：1
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利用有限元流体计算求解器的准备，包括你的使用…
一个用fortran90编写有限元流体求解器，包括使用源代码，输出文件和单元文件，推荐学习使用-Prepared using a finite element fluid fortran90 solver, including the use of source code, the output file and the unit document and recommend learning to use
- 2022-02-03 11:34:16下载
- 积分：1
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Network Hopfield Model
Network Hopfield Model-Hopfield Model Network
- 2022-03-23 14:14:28下载
- 积分：1
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spark并行化的FIM挖掘(apriori,p_growth)
频繁项集挖掘采用spark实现的并行化挖掘算法（并行的apriori算法和b并行的 fp_growth算法）。并行的apriori算法采用scala编写，并行的fpgrowth采用java编写。里面会有较多函数使编程的内容。 &
- 2022-05-08 03:57:50下载
- 积分：1
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sdfsdf sdfsdf sd 自卫队自卫队 sd s fsdfsdf
sdfsdf sdfsdf sd 自卫队自卫队 sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd自卫队自卫队 sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sds fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd 自卫队自卫队 sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf sdfsdf sd sdf sdf sd s fsdfsdfsdfsdf
- 2022-11-04 12:55:03下载
- 积分：1
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issue a travel home to travel home to drive a car with the minimum of cost yi us...
旅行家问题 一个旅行家想驾驶汽车以最少的费yi 用从一个城市到另一个城市（假设出发时油箱是空的）。给定两个城市之间的距离为D1、汽车油箱的容量为C(以升为单位），每升汽油能行驶的距离为 D2，出发点每升汽油价格P和沿途油站数N（N可以为零），油站i离出发点距离Di,每升汽油价格Pi(i=1,2...N)。计算结果四舍五入至小数点后两位。 如果无法到达目的地，则输出“No Solution"。-issue a travel home to travel home to drive a car with the minimum of cost yi used from one city to another city (assuming starting at the fuel tank was empty). Given the two cities for the distance between D1, car fuel tank capacity of the C (in liters) per liter petrol traveling distance to the D2, the starting point liter gasoline prices P and several petrol stations along the N (N can be zero), PFS i distance from the starting point Di per liter Steam oil prices Pi (i = 1,2 ... N). Calculation results rounded to two decimal places. If unable to reach their destination, the export of "No Solution."
- 2023-09-07 00:25:03下载
- 积分：1
