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emv 软件威虎
软件应用的 EMV 软件，创建 ARQC 动态或静态，美味 FUNCIONALITY!!!
- 2022-09-05 18:05:02下载
- 积分：1
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模拟ATM
这是一个基本的ATM模拟和它
- 2023-04-05 03:20:03下载
- 积分：1
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DumpROM源代码，用于WINCE的dumprom.exe工具学习
dumprom source code,use for learning the dumprom.exe tool for wince
- 2022-07-23 18:27:07下载
- 积分：1
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酒店管理系统
通过这个酒店管理系统软件您可以预订一个房间，预定房间、 付款，然后你可以能够利用此示例程序法案的房间详情。
然后这个程序根据虚拟基本的前端。如果你喜欢这请对此发表评论。
- 2023-01-21 17:35:04下载
- 积分：1
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java时间片轮转法
运行RunGame.class文件，和CPU玩21点游戏，
java时间片轮转法
运行RunGame.class文件，和CPU玩21点游戏，-time Web-law running RunGame.class documents, and the CPU play 21:00 games, huh
- 2022-10-26 22:00:03下载
- 积分：1
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AESDemo应用例程 AES（The Advanced Encryption Standard）是美国国家标准与技术研究所用于加密电子数据的规范。它被预期能成...
AESDemo应用例程 AES（The Advanced Encryption Standard）是美国国家标准与技术研究所用于加密电子数据的规范。它被预期能成为人们公认的加密包括金融、电信和政府数字信息的方法。本文展示了AES的概貌并解析了它使用的算法。包括一个完整的C#实现和加密.NET数据的举例。在读完本文后你将能用AES加密、测试 基于AES的软件并能在你的系统中使用AES加密。-The AESDemo application a distance AES( The Advanced Encryption Standard) is a norm that ASCII used for with technique graduate school to encrypt the electronics data.It were expected and can become people encrypt to include the finance, telecommunication generally acceptedly with the method of the government arithmetic figure information.This text displayed the AES all the combines resolution the calculate way that it use.Include a complete C# realizes with encrypt.The data of NET for instance.Use in a reading book over text empress you will can with the AES encrypt, test base on AES software combine can in your system the AES encrypt
- 2022-08-12 12:23:26下载
- 积分：1
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操作系统课程设计, 操作系统课程设计.
操作系统课程设计, 操作系统课程设计.-Operating systems curriculum design, curriculum design the operating system.
- 2022-05-06 20:32:13下载
- 积分：1
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这是本人用ACSESS编的一个销售管理系统，适合直销。
这是本人用ACSESS编的一个销售管理系统，适合直销。-ACSESS series with a sales management system for direct marketing.
- 2022-07-27 15:16:31下载
- 积分：1
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there is a defect in only know that the secret and public key
还有一个缺陷就是在只知道密文 x 及公钥（n,e）的情况下，只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n，此运算不断地循环 e 次之后，很多情况下都可以循环出原文，只是计算量过余多一些罢了。不过有不少情况下，根本都无须循环 e 次，不过对于1024位的 n 级别来说，e 也是一个相当大的数值，所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考，如有不实，请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected
- 2022-03-22 01:18:28下载
- 积分：1
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这是一个用来实现找鞍点的程序，最后输出鞍点所在的横坐标和纵坐标...
这是一个用来实现找鞍点的程序，最后输出鞍点所在的横坐标和纵坐标-Used to realize this is a saddle point finding procedure, the final output saddle point where the abscissa and ordinate
- 2022-08-22 14:41:44下载
- 积分：1
