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混凝土开裂有限元分析
混凝土开裂有限元分析-concrete cracking Finite Element Analysis
- 2022-03-12 14:55:51下载
- 积分：1
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VB中界面特殊效果的实现
VB中界面特殊效果的实现-VB interface to achieve special effects
- 2022-01-24 17:36:08下载
- 积分：1
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嵌入式程序设计基础，谁想看就自己下吧，不错的
嵌入式程序设计基础，谁想看就自己下吧，不错的-Based on embedded programming, who want to see on their own, are you, good
- 2022-06-12 15:29:53下载
- 积分：1
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mfc resources Daquan MFC programming includes all aspects of FOSS
mfc资源大全包含MFC编程各个方面的源码-mfc resources Daquan MFC programming includes all aspects of FOSS
- 2022-01-26 07:09:19下载
- 积分：1
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现代数字信号处理，包括谱估计和基本理论，还有滤波等方面...
现代数字信号处理，包括谱估计和基本理论，还有滤波等方面-Modern digital signal processing, including spectral estimation, and basic theory, as well as filtering, etc.
- 2023-07-09 20:15:06下载
- 积分：1
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徐士良《数值算法与计算》的全书代码
徐士良《数值算法与计算》的全书代码-XU Shi-liang, "Numerical Algorithms and Computation," the code book
- 2022-11-12 15:50:03下载
- 积分：1
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在多数情况下,集成电路芯片的管脚不会全部被使用。例如74ABT16244系列器件最多可以使用16路I/O管脚,但实际上通常不会全部使用,这样就会存在悬空端子。所...
在多数情况下,集成电路芯片的管脚不会全部被使用。例如74ABT16244系列器件最多可以使用16路I/O管脚,但实际上通常不会全部使用,这样就会存在悬空端子。所有数字逻辑器件的无用端子必须连接到一个高电平或低电平,以防止电流漂移（具有总线保持功能的器件无需处理不用输入管脚）。究竟上拉还是下拉由实际器件在何种方式下功耗最低确定。-in most cases, the IC chips will not pin all been used. For example, 74 ABT16244 series device can use up to 16 Road I/O pins. but usually not all use, so there will always be vacant terminal. All digital logic device useless terminals to be connected to a serial or low-level. to prevent the current drift (with the bus maintain functional devices need not deal with the importation of pins). What to draw from the drop-down or what the actual device under way to determine the minimum power consumption.
- 2022-02-09 16:11:50下载
- 积分：1
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肯定对你的编程有很大提高的
肯定对你的编程有很大提高的-sure of your programming has improved a great deal of
- 2022-03-05 04:24:31下载
- 积分：1
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JavaScript的技术参考讲座,对javascript的使用有全面的描述。
JavaScript的技术参考讲座,对javascript的使用有全面的描述。-Technical reference JavaScript lectures, the use of javascript has a comprehensive description.
- 2022-09-20 16:30:03下载
- 积分：1
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舞伴问题假定在一舞会上，男士排成一队，女士排成一队。跳舞开始时，依次从男队和女队的队头各出一人配成舞伴。若两队初始人数不相同，则较长的那一队中未配对者等待下一轮...
舞伴问题假定在一舞会上，男士排成一队，女士排成一队。跳舞开始时，依次从男队和女队的队头各出一人配成舞伴。若两队初始人数不相同，则较长的那一队中未配对者等待下一轮舞曲。设计要求：模拟上述舞伴系统，并能计算对于任何男士A和女士B在哪一轮舞曲中的k次跳舞？ -Question assumes that a dance partner, the men line up a team, ladies and line up a team. Dancing began, followed by men" s and women" s team from the team dubbed the first one from each partner. If the initial number of teams is not the same, then the longer of that team who is not waiting for the next round of the dance pairs. Design requirements: Analog the partner system, and can calculate for any men" s A and women dance in B in which a k-dance?
- 2022-03-09 22:16:12下载
- 积分：1
