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软件质量是由大多数程序员的头脑和不只是吨。
软件质量是被大多数程序员挂在嘴上而不是放在心上的东西！
除了完全外行和真正的编程高手外，初读本书，你最先的感受将是惊慌：“哇！我以前捏造的C++/C程序怎么会有那么多的毛病？”
别难过，作者只不过比你早几年、多几次惊慌而已。
请花一两个小时认真阅读这本百页经书，你将会获益匪浅，这是前面N-1个读者的建议。
-software quality is linked by the majority of programmers in mind and not just the things! In addition to completely out of the loop and genuine master of programming, early Reader book, you will be the first to the feelings of panic : "wow! I used to fabricate the C/C program how did so many of the defects? "Do not sorry The author only a few years than you, it more often panic. Please spend 12 hours reading this book by 100, you will be benefited, which is in front of N-a suggestion of the readers.
- 2022-10-28 14:30:04下载
- 积分：1
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Here are two newest published articles talking about joint source channel coding...
Here are two newest published articles talking about joint source channel coding, in which source coding is invovled scalable video coding. They are very useful for people who are doing research about it. -Here are two newest published articles talking about joint source channel coding, in which source coding is invovled scalable video coding. They are very useful for people who are doing research about it.
- 2022-02-27 02:45:57下载
- 积分：1
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还有一个缺陷就是在只知道密文 x 及公钥（n,e）的情况下，只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n，此运算不...
还有一个缺陷就是在只知道密文 x 及公钥（n,e）的情况下，只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n，此运算不断地循环 e 次之后，很多情况下都可以循环出原文，只是计算量过余多一些罢了。不过有不少情况下，根本都无须循环 e 次，不过对于1024位的 n 级别来说，e 也是一个相当大的数值，所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考，如有不实，请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected
- 2022-08-03 02:51:21下载
- 积分：1
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23种设计模式的Java实现,对23种模式有详细的介绍，还有代码的解释。...
23种设计模式的Java实现,对23种模式有详细的介绍，还有代码的解释。-pattern in java
- 2022-03-25 04:28:07下载
- 积分：1
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Perl Languages
Perl Languages
Perl Languages
Perl 语言入门(第四版).pdf
Perl 语言入门(第四版).pdf-Perl Languages
Perl Languages
Perl Languages
- 2022-02-03 10:23:25下载
- 积分：1
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用C sharp
附带了数据库的餐饮系统，大家一起学习学习，有什么不好的地方多多体谅-writed by C Sharp
- 2022-03-22 04:15:04下载
- 积分：1
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23中设计模式大家都应该知道吧，我从别处收集过来的，书里面讲解清晰明了，里面的例子可以直接编译通过，这个是创建型模式...
23中设计模式大家都应该知道吧，我从别处收集过来的，书里面讲解清晰明了，里面的例子可以直接编译通过，这个是创建型模式-23中设 ?颇 ???
- 2022-01-25 23:48:31下载
- 积分：1
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模拟退火算法求解TSP问题.求解TSP问题的模拟退火算法
模拟退火算法求解TSP问题.求解TSP问题的模拟退火算法-simulated annealing algorithm for TSP. TSP simulated annealing
- 2022-03-20 00:02:41下载
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Idea.Group.Publishing.UML.And.The.Unified.Process
介绍UML和unified process的电子书...
Idea.Group.Publishing.UML.And.The.Unified.Process
介绍UML和unified process的电子书-UML Introduction Idea.Group.Publishing.UML.And.The.Unified.Process and unified process of e-books
- 2022-11-09 04:30:03下载
- 积分：1
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ARM7
ARM7的LCD应用程序，在液晶显示屏上可以显示出所需图形-ARM7-LCD applications, on the LCD screen can display graphics required
- 2022-03-31 00:16:39下载
- 积分：1
