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lcd_panel_cfg
这是基于UCOS的LCD显示驱动，LCD为RGB+SPI模式。希望对大家有用。(This is LCD driver based on UCOS，the model of LCD is RGB+LCD.Wish help for you。)
- 2012-03-28 18:07:29下载
- 积分：1
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PV_fixed_step
基于MATLAB/SIMULIN，搭建的光伏系统最大功率跟踪爬山法的定步长模型(Structures of the PV system based on MATLAB/SIMULIN, climbing method of maximum power point tracking fixed step model)
- 2012-10-17 10:52:05下载
- 积分：1
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bcjrforcpm
用bcjr算法对cpm连续相位调制进行译码的程序，按照IEEE leter 2000年文章写的(Cpm with bcjr algorithm for continuous phase modulation decoding process, in accordance with IEEE leter 2000 writing the article, written by)
- 2021-01-05 17:58:54下载
- 积分：1
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彩色图像的合成vc代码
说明： 一个较好效果的彩色图像合成代码(分左右两个视窗,点击左边的视窗后显示左图,选择操作后,点击右视窗,可看到各种不同合成操作的效果图)(a good result Color Image Synthesis code (around two windows, Click on the left side of the window shows the municipality, the choice of operation, click on the right window we can see various synthesis operating results))
- 2006-02-22 23:06:48下载
- 积分：1
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TestDosCaihuang
临时开TELNET临时开启产测的功能，方便产线更快的作业，不需要进网页(Temporarily open TELNET temporarily open the production test function, convenient production line faster operation, do not need to enter the web page)
- 2017-11-22 20:29:40下载
- 积分：1
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使用 GraphCut 的合成图像
使用 opencv3.0 和 c + +，graphcuts 展示合成图像
- 2022-07-09 12:41:58下载
- 积分：1
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新SPI版0.96寸OLED显示屏资料蓝色
0.96寸OLED驱动，avr c51 stm8 stm32驱动(0.96 inch OLED driver, AVR C51 stm8 STM32 driver)
- 2020-11-20 10:49:36下载
- 积分：1
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其实学Delphi并不难，看你的努力程度，我才学了一个学期，就已经可以做一些小的应用软件了，
现在在接做两个大的系统，首先要相信自己，才能有可能成功，找些好...
其实学Delphi并不难，看你的努力程度，我才学了一个学期，就已经可以做一些小的应用软件了，
现在在接做两个大的系统，首先要相信自己，才能有可能成功，找些好的书，如《DELPHI编程技巧与实例》等，-Actually, academic Delphi is not difficult to see your efforts, I scholarship for a semester. it can do some small software applications, now done in the following two systems, we must first believe in themselves and may be successful, and find some good books, like "Delphi programming techniques and examples."
- 2022-03-03 14:28:51下载
- 积分：1
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calculator
这是基于单片机的计算器程序，可以实现加减乘除的功能(This is based on single-chip calculator program, Math functions can be achieved)
- 2011-11-11 13:32:40下载
- 积分：1
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Maze-code
以一个m×n的长方阵表示迷宫，0和1分别表示迷宫中的通路和障碍。设计一个程序，对任意设定的迷宫，求出一条从入口到出口的通路，或得出没有通路的结论。首先用二维数组存储迷宫数据，迷宫数据由用户输入。一个以链表作存储结构的栈类型，然后编写一个求解迷宫的递归或非递归程序。求得的通路以三元组（i，j，d）形式输出，其中：（i，j）指示迷宫中的一个坐标，d表示走到下一坐标的方向（东、南、西、北四个方向所用代表数字，自行定义） (With an m × n the long square maze, 0 and 1, respectively maze of pathways and obstacles. Design a program, for any set of the maze, find a path from the inlet to the outlet, or come to the conclusion there is no path. First of a two-dimensional array to store the data maze, maze data input by the user. A linked list storage structure for stack type, and then write a recursive or non-recursive solving the maze procedure. Obtained access to triples (i, j, d) in the form of output, of which: (i, j) indicates the maze of a coordinate, d represents the coordinates walked next direction (east, south, west, north four directions used on behalf of a digital, self-defined))
- 2014-01-20 15:41:40下载
- 积分：1
