-
ucosii的GUI
ucos GUI源代码,大家参考参考。不知道为什么字符还不够啊。-ucosii GUI
- 2022-06-13 01:19:08下载
- 积分:1
-
这个文件最初在一个m
这个文件最初在一个m-ix86pm的UCOS For 386包中,
但是没有源代码,原名叫ExeToImg.EXE
用于将PE结构的EXE文件转换为内存映像文件,
可用于在WIN平台上开发基于x86的操作系统
这个源代码编译后效果跟原版差不多,是我用OllyDBG反编译写成C的.
对于学习PE文件及操作系统有一定作用,
毕竟我的大部分的操作是在window下,
机器差得要得,不想用虚拟机在linux下编译入门的操作系统.
像中的Tinux
-This document was originally in a m-ix86pm the UCOS For 386 package, but no source code, the original name used to ExeToImg.EXE structure of PE files into memory EXE image file that can be used in the WIN platform x86-based operating system of the source code compiled with the original effect is almost that I wrote with OllyDBG decompile C
- 2022-03-22 06:43:00下载
- 积分:1
-
磁盘调度算法 1。实现三种算法: 1。先来先服务 2。最短寻道优先(可自己假设当前磁头的位置) 3。电梯算法 2。磁道服务顺序从指定的...
磁盘调度算法 1。实现三种算法: 1。先来先服务 2。最短寻道优先(可自己假设当前磁头的位置) 3。电梯算法 2。磁道服务顺序从指定的文本文件(TXT文件)中取出 3。输出: 第一行:磁道的服务顺序 第二行:显示移动总道数-a disk scheduling algorithms. Three algorithms to achieve : 1. First-come first-serve two. Seeking shortest priority (to be their head the assumption that the current location) 3. Elevator Algorithm 2. Track services from the designated order of the text document (TXT) out of three. Output : the first line : track the order of the second line services : Road show that the total number of mobile
- 2022-08-15 21:13:09下载
- 积分:1
-
操作系统课程设计,模拟UNIX磁盘文件管理系统
• 建立文件存储介质的管理机制
• 建立目录
• 文件系统功能(显示目...
操作系统课程设计,模拟UNIX磁盘文件管理系统
• 建立文件存储介质的管理机制
• 建立目录
• 文件系统功能(显示目录、创建、删除、打开、关闭、读、写)
• 文件操作接口(显示目录、创建、删除、打开、关闭、读、写)-Operating system, curriculum design, simulation UNIX disk file management system • Create file storage media management mechanisms • • File system functions to create the directory (show directory, create, delete, open, close, read, write) • File Operation Interface (show directory, create, delete, open, close, read, write)
- 2023-02-17 07:05:03下载
- 积分:1
-
MIZI Linux SDK的S3C2410核心linux-2.4.18
MIZI Linux SDK的S3C2410核心linux-2.4.18它的所有
- 2022-01-30 16:02:05下载
- 积分:1
-
试验目的:通过研究Linux的线程机制和信号量实现生产者消费者问题的并发控制 说明:有界缓冲区内设有20个存储单元,放入/取出的数据项设定为1~20这20个整型...
试验目的:通过研究Linux的线程机制和信号量实现生产者消费者问题的并发控制 说明:有界缓冲区内设有20个存储单元,放入/取出的数据项设定为1~20这20个整型数。 要求: (1)每个生产者和消费者对有界缓冲区进行操作后,即时显示有界缓冲区的全部内容.当前指针位置和生产者/消费者线程的标识符 (2)生产者和消费者各有两个以上 (3)多个生产者或多个消费者之间须共享对缓冲区进行操作的函数代码。-Test Objective : To study the Linux threading mechanism and signal to producers and consumers to achieve the concurrency control : a boundary buffer There are 20 storage units, Add/remove data items for a set of 20 ~ 20-integer. Requirements : (1) Each producer and consumer sector of the buffer zone is operated, immediately after the sector showed a buffer in its entirety. The current position and producer/consumer threads identifier (2) producers and consumers have two or more (3) A number of producers or many consumers to be shared between the right to operate the buffer function code.
- 2023-06-17 09:40:03下载
- 积分:1
-
source code of Stanford iPhone course, demo of how to use multitouch
Stanford iPhone课程配套源码,介绍multitouch 的实现方法。-source code of Stanford iPhone course, demo of how to use multitouch
- 2022-04-08 04:20:10下载
- 积分:1
-
ncurses
ncurses-5.4 需要的就来下把 一定会有用的哦-ncurses-5.4 needed on to the next will be used to Oh
- 2023-07-26 20:50:04下载
- 积分:1
-
In layman
深入浅出ARM7-LPC213x_214xEmbedded_systems_architecture_Programming_and_Design-In layman
- 2022-07-01 11:28:27下载
- 积分:1
-
操作系统引导探究
操作系统引导探究-OS guide Inquiry
- 2022-08-08 21:43:48下载
- 积分:1