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组合问题,从M个不同字符中任取N个字符的所有组合
组合问题,从M个不同字符中任取N个字符的所有组合-Combination of issues, from the M different characters of any N-character check all combinations
- 2022-02-21 08:01:01下载
- 积分:1
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Delphi SQL数据库浏览器
Delphi SQL数据库浏览器。可以连接数据库并对表中的数据进行查询修改。
- 2022-02-06 05:45:49下载
- 积分:1
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数据结构
数据结构--树的常见操作及维护算法的实现-data structure-- a common tree operation and maintenance of the algorithm to achieve
- 2022-06-16 13:51:04下载
- 积分:1
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C语言数据结构课件及复习题和一些技术的讲解
C语言数据结构课件及复习题和一些技术的讲解-C language data structures courseware and review questions and a number of technologies on
- 2023-08-07 22:05:06下载
- 积分:1
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ADO直接读取数据库的编程实例
ADO直接读取数据库的编程实例-read directly ADO database programming examples
- 2022-03-29 12:09:20下载
- 积分:1
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an improved Boyer
一种改进的Boyer-Moore的字符串查找算法,并封装到类-an improved Boyer- Moore string search algorithms, and type of packaging
- 2022-03-22 09:29:48下载
- 积分:1
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最段路径算法C++实现 实现工程清晰可见 仅供参考
最段路径算法C++实现 实现工程清晰可见 仅供参考-Most paragraphs path algorithm C++ Realize realize the project clearly visible for reference only
- 2022-01-30 15:48:14下载
- 积分:1
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广义表的反序
逆置广义表的递归模型如下:
F(LS) = null 若 LS 为空
F(LS) = LS ...
广义表的反序
逆置广义表的递归模型如下:
F(LS) = null 若 LS 为空
F(LS) = LS 若 LS 为原子,且 tail(LS) 为空
F(LS) = append( F(tail(LS)), head(LS) ) 若 LS->tag=0 ,且 LS->tp!=null
F(LS) = append( F(tail(LS), F(head(LS)) ) 若 LS->tag=1
其中 append(a,b) 的功能是将广义表 a 和 b 作为元素的广义表连接起来。-Generalized table set against the broad anti-order recursive model of the table is as follows: F (LS) = null if the LS is empty F (LS) = LS if LS for the atoms, and the tail (LS) is empty F (LS) = append (F (tail (LS)), head (LS)) if the LS-> tag = 0, and the LS-> tp! = null F (LS) = append (F (tail (LS), F (head (LS))) If the LS-> tag = 1 where append (a, b) function is a generalized form, and b as elements of generalized tables connected.
- 2022-03-01 20:55:59下载
- 积分:1
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c程序各种经典算法
c程序各种经典算法-various classical algorithm
- 2022-03-04 17:12:52下载
- 积分:1
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小型数据库源代码较多,请耐心审阅勿用于商业交易,一经发现后果自负...
小型数据库源代码较多,请耐心审阅勿用于商业交易,一经发现后果自负-small database source code more, not patience scrutiny for commercial transactions, the one found responsible for any consequences! !
- 2022-06-12 22:29:41下载
- 积分:1