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多线程控制多辆小车的运行仿真
使用多线程控制多辆小车,可进行速度与车辆数的设置,模拟小车在物流园区内的运行,从而检验运输效率。线程代表小车
- 2023-03-22 09:30:04下载
- 积分:1
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许多不是太难的C常用算法程序。初学者不妨一个个的研究下,很基础,很有必要。涵盖功能很多,不一一列举。...
许多不是太难的C常用算法程序。初学者不妨一个个的研究下,很基础,很有必要。涵盖功能很多,不一一列举。-Not too many of C procedures commonly used algorithms. Beginners may wish to study one by one, the very foundation, it is necessary. Covers many functions, not added to the list.
- 2022-02-03 04:29:10下载
- 积分:1
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Windows 环境下设备驱动程序设计,很好的资料,拿来共享
Windows 环境下设备驱动程序设计,很好的资料,拿来共享-Windows environment, device driver design, very good information, brought to share
- 2022-05-18 02:40:16下载
- 积分:1
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VC access through OnGetCOMObject () function to achieve access to communications...
VC++获取通过OnGetCOMObject() 函数实现获取通讯端口对象。-VC access through OnGetCOMObject () function to achieve access to communications ports targets.
- 2023-05-26 12:55:02下载
- 积分:1
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Find their own network programming is also about the source of the serial
自己找得网络编程的源程序 也是关于串口的-Find their own network programming is also about the source of the serial
- 2023-02-08 05:00:04下载
- 积分:1
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获取local地址程序,应该不错哦,能对一部分初学着有用
获取local地址程序,应该不错哦,能对一部分初学着有用-Procedures to obtain local address, it should be good Oh, can a useful part of learning
- 2022-03-02 10:30:24下载
- 积分:1
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基于RMI1250(MIPS 32内核)通过GPIO模拟IIC驱动源码,在WinCE 5.0下测试通过...
基于RMI1250(MIPS 32内核)通过GPIO模拟IIC驱动源码,在WinCE 5.0下测试通过-Based on RMI1250 (MIPS 32 core) through the GPIO analog source IIC driver in WinCE 5.0 under the test
- 2022-03-11 03:32:47下载
- 积分:1
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相信计算机专业的学生在学《编译原理》时都做了有关求first和follow集的问题。此程序用VC++做,相信会给大家一定的帮助。...
相信计算机专业的学生在学《编译原理》时都做了有关求first和follow集的问题。此程序用VC++做,相信会给大家一定的帮助。-it s sure that the student of computer do first and follow when learning . This program uses vc++,and i am sure it is useful for everyone!
- 2023-01-19 12:55:03下载
- 积分:1
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易语言写的小工具带源码 各种进制数据转换
易语言写的小工具带源码 各种进制数据转换-Easy language to write a small tool with a variety of binary source data conversion
- 2023-04-07 11:10:03下载
- 积分:1
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In order to write data or write, we should first check the status of LCM, or sta...
在写数据或写命令之前,应先检查LCM的状态,即状态寄存器中命令就绪(STA0)和数据就绪(STA1)需要同时检查,只有这两位同时为“1”(LCM空闲状态)时,才可以进行数据和命令的写操作,通常情况下,可以设计一个读状态子函数,用以判断-In order to write data or write, we should first check the status of LCM, or status register in the order in place (STA0) and data-ready (STA1) need to check that only the two at the same time
- 2022-02-13 02:13:08下载
- 积分:1