-
ORACLE课程设计(5个代码段)
ORACLE课程设计(5个代码段)-ORACLE curriculum design (5 code)
- 2022-11-21 11:05:03下载
- 积分:1
-
数据结构 算法与应用
C++语言描述
机械工业出版社,完全非扫描高清版
配有答案和程序...
数据结构 算法与应用
C++语言描述
机械工业出版社,完全非扫描高清版
配有答案和程序-Data structures algorithms and application of C++ Language description of Machinery Industry Press, completely non-scanning high-definition version with the answer and procedures
- 2022-01-21 19:59:49下载
- 积分:1
-
本程序是一个用树常用算法,信号…
本程序是实现二叉树跟树的常用算法,都是尽量用非递归来编写的。关于二叉树的都可以从键盘动态输入,关于树的就不可以,原因是树的结构问题,在程序中,树的建立用到动态左孩子/右孩子建立-this program is a binary tree with the tree is commonly used algorithm, as possible, to use non- recursive prepared. On the binary tree can be dynamic input from the keyboard, on the tree will not be able to because of the tree structure, in the process, the tree is used to establish dynamic children left/right to establish child
- 2023-08-03 16:20:02下载
- 积分:1
-
51单片机大量源码
这是为初学者提供的,可以在短时间内学会,只要你有耐心,只要你有恒心,你就会学会,真的一点也不难。只要你肯下功夫。
- 2023-07-16 09:50:04下载
- 积分:1
-
Order to map any of the distance between two nodes, (2) with two
求图的任两结点间的距离,(2) 用二维数组存放C和A ,C是原成本矩阵,A 是求出的距离矩阵
(3) 算法采用三重循环,其中最外层的循环变量必须代表中间结点,中层的循环变量代表头结点而内层循环变量代表尾结点。
(4) 试着把三层循环变量的顺序作些改变,最外层的循环变量仍代表中间结点,而中层循环变量代表尾结点,内层循环变量代表头结点。把两种做法所得结果作比较,看结果是否相同
(5) 显示结果要清晰易懂
(6) 本题运行结果
-Order to map any of the distance between two nodes, (2) with two-dimensional array of storage C, A, C is the original cost matrix, A is to find the distance matrix (3) The algorithm uses the triple loop, one of the most outer loop variable must be representative of intermediate nodes, the middle loop variable represents the first node and the inner loop variable represents the end nodes. (4) tried to three-loop order of the variables to make some changes, the most outer loop variables still represent intermediate nodes, while the middle loop variable represents the end nodes, the inner loop variable represents the first node. The two approaches to compare the results to see whether the results the same (5) shows the results must be clear and understandable (6) The q
- 2022-04-20 12:55:19下载
- 积分:1
-
实现Haffman算法,有输入的接口,需输入字符及其权重,能自动生成Haffman编码...
实现Haffman算法,有输入的接口,需输入字符及其权重,能自动生成Haffman编码-achieve Haffman algorithm, the input interface, the need to import characters and weights, can automatically generate code Haffman
- 2022-06-20 08:47:40下载
- 积分:1
-
酷Grid控件示例
... ..cj.CDX
..............cj.dbf
..............MyGrid.SCT...
酷Grid控件示例
... ..cj.CDX
..............cj.dbf
..............MyGrid.SCT
..............MyGrid.scx
..............MZ.DBF
..............
eadme.dbf
..............
eadme.FPT
..............
eadme.txt
..............xsda.CDX
..............xsda.dbf -Cool Grid Control example .............. cj.CDX ...... ........ cj.dbf .............. MyGrid.SCT .............. MyGrid.scx .............. MZ.DBF .............. readme.dbf ......... ..... readme.FPT .............. readme.tx t .............. xsda.CDX .............. x sda.dbf
- 2022-01-25 18:42:47下载
- 积分:1
-
在线投票系统,本系统采用myeclipse开发工具,结合sqlserver2000数据库。完成一个在线投票系统...
在线投票系统,本系统采用myeclipse开发工具,结合sqlserver2000数据库。完成一个在线投票系统-Online voting system, this system development tools myeclipse, combined with sqlserver2000 database. Completion of an online voting system
- 2022-09-16 01:30:03下载
- 积分:1
-
求单源点最短路径算法,对一个途中各个节点和权值的设置,找出从起始点倒终结点的一条最短路径,不能够输出路径...
求单源点最短路径算法,对一个途中各个节点和权值的设置,找出从起始点倒终结点的一条最短路径,不能够输出路径
- 2022-10-06 18:00:02下载
- 积分:1
-
sql数据库电子书
sql数据库电子书-sql database e-books
- 2022-08-09 04:36:33下载
- 积分:1