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心电数据分类器
心电数据分类、 特征提取进行离散余弦变换,然后分类,由神经的解决办法,数据也是可用。A算法求解二次规划 (QP) 出现的问题,在训练期间。
- 2022-01-23 11:16:49下载
- 积分:1
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liquidation registry source of refuse
清算登记处拒绝来源
- 2022-05-26 19:11:00下载
- 积分:1
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BMPnewone位图处理源代码
BMPnewone位图处理源代码-BMPnewone bitmap processing source code
- 2022-06-11 22:23:01下载
- 积分:1
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IE风格工具条,定时关机
IE风格工具条,定时关机-IE style tools, Mytob.BSNotes
- 2022-02-15 20:50:15下载
- 积分:1
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如何锁定 ListView 的栏目头宽度
如何锁定 ListView 的栏目头宽度-how to lock the width of the first column
- 2022-01-21 01:31:32下载
- 积分:1
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download music for the procedure
用于音乐下载的程序-download music for the procedure
- 2022-08-20 06:05:10下载
- 积分:1
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there is a defect in only know that the secret and public key
还有一个缺陷就是在只知道密文 x 及公钥(n,e)的情况下,只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n,此运算不断地循环 e 次之后,很多情况下都可以循环出原文,只是计算量过余多一些罢了。不过有不少情况下,根本都无须循环 e 次,不过对于1024位的 n 级别来说,e 也是一个相当大的数值,所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考,如有不实,请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected
- 2022-03-22 01:18:28下载
- 积分:1
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克拉斯尔算法。从图中的矩阵
kraskal algorithm. making a matrix from the graph
- 2022-09-07 13:30:03下载
- 积分:1
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1 pairs of control panel (Control Panel) operated source code
一个对控制面板(Control Panel)操作的源程序 -1 pairs of control panel (Control Panel) operated source code
- 2023-08-09 19:50:03下载
- 积分:1
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VC++的文件操作函数,可以遍历指定目录下的所有或指定类型的文件....
VC++的文件操作函数,可以遍历指定目录下的所有或指定类型的文件.-VC++ The file manipulation functions, you specify a directory traversal of all or specified types of files.
- 2022-03-18 00:39:42下载
- 积分:1